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3 years ago

What is the hight of something if the volume is 22.05 the length is 3.5 and the width is 4.2

1 answer:

7 0

Volume is the product of lenght (L) width (W) and hight (H)

$V=L*W*H\\\\ 22.05=3.5*4.2*H\\\\ 22.5=14.7*H\\\\ 14.7*H=22.5\\\\
H=22.5:14.7\\\\H=\frac{22.5}{14.7}\\\\H=\frac{225}{147}\\\\H=1\frac{78}{147}\\\\H=1\frac{26}{49}\\\\H\approx1,53$

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A rectangular family room is 18 feet long and 14 feet wide.

Firlakuza [10]

Answer:

4 pieces of chair rail are needed

Step-by-step explanation:

Step 1: Calculate the perimeter of the room

Perimeter of rectangle = 2L + 2B

Length = 18

Breadth = 14

Perimeter of room = 2(18) + 2(14)

Perimeter of room = 64 feet

Step 2: Calculate the pieces of chair rail needed

Perimeter of room = 64 feet

Length of each chair rail = 16 feet

Total chair rails needed = Perimeter of room/length of each chair rail

Total chair rails needed = 64/16

Total chair rails needed = 4

Therefore, Mr. Herzog needs 4 pieces of chair rails.

5 0

3 years ago

Find sin θ if θ is in Quadrant III and tan θ = -1/5

Alborosie

Answer:= - sin( square root 8 over 3)sin(1/4)

Step-by-step explanation:

So I did (square root 8/3)(square root 15/4)+sin(1/4)cos(-1/3) divide that by (-1/3)(square root 15 over 4) - sin( square root 8 over 3)sin(1/4)

4 0

2 years ago

I’m stuck on this question. any help would be greatly appreciated

Mademuasel [1]

Using the Pythagorean theorem we get:

$y^2+8^2=12^2.$

Simplifying the above result we get:

$y^2+64=144.$

Subtracting 64 from the above equation we get:

$\begin{gathered} y^2+64-64=144-64, \\ y^2=80. \end{gathered}$

Therefore:

$y=\sqrt{80}\approx8.9.$

Answer:

$y=8.9.$

4 0

2 years ago

(-102.75) ÷(-3) round to the nearest hundredth

astra-53 [7]

Answer:34.17

Step-by-step explanation:

(-102.5) ➗ (-3)=34.17

6 0

3 years ago

Read 2 more answers

Find the average value of the function f(t)=cos13(5t)sin(5t) f(t)=cos13⁡(5t)sin⁡(5t) on the interval [4,10].

Vilka [71]

The average value is given by

$\displaystyle\frac1{10-4}\int_4^{10}\cos^{13}5t\sin5t\,\mathrm dt$

Setting $y=\cos5t$ , you get $\mathrm dy=-5\sin5t\,\mathrm dt$ , and the integral becomes

$\displaystyle-\frac1{30}\int_{\cos20}^{\cos50}y^{13}\,\mathrm dy$
$=-\dfrac1{30}\dfrac{y^{14}}{14}\bigg|_{y=\cos20}^{y=\cos50}$
$=-\dfrac{\cos^{14}50-\cos^{14}20}{420}\approx-0.00145$

6 0

4 years ago