The initial value is 3 (when x=0), and the multiplier is 2, when x=2. The equation can be written as
.. y = 3*(2^(x/2))
Step-by-step explanation:
You have to do first and second derivatives :
y = a sin 3x + b cos 3x
dy/dx = 3a cos 3x - 3b sin 3x
d²y/dx² = - 9a sin 3x - 9b cos 3x
Next, you have to compare it :
let d²y/dx² = ky,
-9a sin 3x - 9b cos 3x = k(a sin 3x + b cos 3x)
-9(a sin 3x + b cos 3x) = k(a sin 3x + b cos 3x)
Therefore, k is equals to 9.
Answer:
Step 1: Multiply 1x5 Step 2: Multiply 2x3 Step 3: Add the two products
d=v*t
d=distance
v=velocity(speed)
t=time
distance is equal to the product of velocity and time, equation form;
d=vt
Any questions please feel free to ask. Thanks!
20 - 7 = 13
8 - 13 = 5
13 + 5 = 18
20 - 18 = 2
So two is your answer because.....
13 + 5 + 2 = 20
