Next time, please share your system of linear equations by typing only one equation per line:
<span>3x - 2y - 7 = 0 5x + y - 3 = 0 NO
</span><span>3x - 2y - 7 = 0
5x + y - 3 = 0 YES
Mult. the 2nd equation by 2 so as to obtain 2y, which will be cancelled out by - 2y in the first equation:
</span><span> 3x - 2y - 7 = 0
2(5x + y - 3 = 0)
Then:
3x - 2y - 7 = 0
10x +2y - 6 = 0
----------------------
13x - 13 = 0, so that x = 1. Find y by subbing 1 for x in either of the 2 given equations.</span>
Cut the shape into shapes you know the area of and do the formula this helps
Answer:
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Step-by-step explanation: because its online
Answer:
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Step-by-step explanation:
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(x^2) <64 => (x^2) -64 < 64-64 => (x^2) - 64 < 0 64= 8^2 so (x^2) - (8^2) < 0 To solve the inequality we first find the roots (values of x that make (x^2) - (8^2) = 0 ) Note that if we can express (x^2) - (y^2) as (x-y)* (x+y) You can work backwards and verify this is true. so let's set (x^2) - (8^2) equal to zero to find the roots: (x^2) - (8^2) = 0 => (x-8)*(x+8) = 0 if x-8 = 0 => x=8 and if x+8 = 0 => x=-8 So x= +/-8 are the roots of x^2) - (8^2)Now you need to pick any x values less than -8 (the smaller root) , one x value between -8 and +8 (the two roots), and one x value greater than 8 (the greater root) and see if the sign is positive or negative. 1) Let's pick -10 (which is smaller than -8). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0 so it is positive
2) Let's pick 0 (which is greater than -8, larger than 8). If x=0, then (x^2) - (8^2) = 0-64 = -64 <0 so it is negative3) Let's pick +10 (which is greater than 10). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0 so it is positive Since we are interested in (x^2) - 64 < 0, then x should be between -8 and positive 8. So -8<x<8 Note: If you choose any number outside this range for x, and square it it will be greater than 64 and so it is not valid.
Hope this helped!
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