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makkiz [27]
3 years ago
13

"Replication forks from the same origin of replication extend __________. __________ DNA strand is used as template for the lead

ing strand at one fork and for the lagging strand at the second fork. New DNA is synthesized from 5' to 3' on the __________."
Biology
1 answer:
cluponka [151]3 years ago
5 0

Answer:

Explanation:

Replication forks from the same origin of replication extend from the beginning of the strand to the end where the enzyme helicase helps to move the replication fork unwinding DNA double helix structure by breaking the hydrogen bonds between the Nitrogenous bases.

DNA strand is used as template for the leading strand at one fork and for the lagging strand at the second fork. New DNA is synthesized from 5' to 3' on the leading strand.

The strand is made continuously forward in the direction of the replication fork while the other strand is made in 3' to 5' direction and been referred to as ozazaki fragments.

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Industrial melanism refers to the dark pigmentation that evolved in some insects giving them protective coloration on vegetation
Natalka [10]

Answer:

  • The frequency of the dominant allele, p =  0.542
  • The proportion of black moths that are heterozygous 2pq = 0.496

Explanation:

According to Hardy-Weinberg, the allelic frequencies in a locus are represented as p and q, referring to the allelic dominant or recessive forms. The genotypic frequencies after one generation are p² (Homozygous dominant), 2pq (Heterozygous), q² (Homozygous recessive). Populations in H-W equilibrium will get the same allelic frequencies generation after generation. The sum of these allelic frequencies equals 1, this is p + q = 1.

In the same way, the sum of genotypic frequencies equals 1, this is

p² + 2pq + q² = 1

Being

  • p the dominant allelic frequency,
  • q the recessive allelic frequency,
  • p² the homozygous dominant genotypic frequency
  • q² the homozygous recessive genotypic frequency
  • 2pq the heterozygous genotypic frequency

In the exposed example, 79% of the moths of the species Biston betularia were black due to the presence of a dominant gene for melanism.

If the genotypic frequency of back moths is 0.79, then, by performing the following equation we can get the not-black moths genotypic frequency:

p² + 2pq + q² = 1

where p² is the homozygous dominant genotypic frequency, q² the homozygous recessive genotypic frequency, and 2pq is the heterozygous genotypic frequency.

As 0.79 is the phenotypic frequency of black moths, then this frequency equals p²+2pq.

Clearing the equation:

p² + 2pq + q² = 1

0.79 + q² = 1

q² = 1 - 0.79

q² = 0.21

The genotypic frequency of non-black moths is 0.21. So, from here we can calculate the allelic frequency:

q² = 0.21

q= v 0.21

q = 0.458

If 0.46 is the allelic frequency of non-black moths, then by clearing the equation p + q = 1, we can get the p allelic frequency:

p + q = 1

p + 0.458 = 1

p = 1 - 0.458

p = 0.542

  • The genotypic frequency p² = (0.542)² = 0.294
  • The heterozygote genotypic frequency

        2 x p x q = 2 x 0.542 x 0.458 = 0.496

Finally, we can check this answer by clearing the following equation:

p² + 2pq + q² = 1

0.294 + 0.496 + 0.21 = 1                  

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Why do you think William Morgan invented the sport mintonette? what do you think is the purpose?​
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Answer:

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