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Novosadov [1.4K]
4 years ago
8

461÷301 give the answer​

Mathematics
1 answer:
Oksanka [162]4 years ago
8 0

1.53156146179 that is the answer

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zhuklara [117]

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distributive property

Step-by-step explanation:

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What is the equivalent fraction to 2/6
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1/3
*Tip: Just divide each side by the same number (in this case, divide each side by 2)

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It took Kelly 5 2/3 hours to fly from City A to City B then it took her another 2 3/5hours to fly from City B toCity C. Kelly fl
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Answer:

eto na po

Step-by-step explanation:

5 2/3 × 2 3/5 = 5 6/15 answer

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The function g is related to one of the parent functions g(x) = x2 – 3 The parent function is: f(x)= x^2 Use function notation t
krek1111 [17]

g(x) is a translation of f(x), we have:

g(x) = f(x) - 3

<h3>How to write g(x) in terms of f(x)?</h3>

We have the two functions:

g(x) = x^2 - 3\\\\f(x) = x^2

We can see that g(x) is just a translation of 3 units downwards of f(x), to write g(x) in terms of f(x) we can just replace the first term by f(x):

g(x) = x^2 - 3 = f(x) - 3

So we have:

g(x) = f(x) - 3

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6 0
2 years ago
Commuting. there are two routes he could take to work. Aneighbor who has lived there a long time tells him Route Awill average 5
iren2701 [21]

Answer:

a)We are 95% confident that the average commuting time for route A is between 1.3577 and 4.6423 minutes shorter than the average committing time for rout B.  

(b) No, because the confidence internal does not contain —5, which corresponds with an average of 5 minutes shorter for route A.

Step-by-step explanation:

Given:  

n_1 = 20

x_1= 40

s_1 = 3

n_2 = 20

x_2= 43

s_2 = 2

d_f = 33.1

c = 95%. 0.95

(a) Determine the t-value by looking in the row starting with degrees of freedom df = 33.1 > 32 and in the column with c = 95% in the Student's t distribution table in the appendix:  

t\alpha/2 = 2.037  

The margin of error is then:  

E = t\alpha/2 *√s_1^2/n_1+s_2^2/n_2

E = 2.037  *√3^2/20+s_2^2/20

  = 1.64

The endpoints of the confidence interval for u_1 — u_2 are:  

(x_1 — x_2) — E = (40 — 43) — 1.6423 = —3 — 1.6423= —4.6423

(x_1 - x_2)  + E   = (40 — 43) + 1.6423 = —3 + 1.6423= —1.3577  

a)We are 95% confident that the average commuting time for route A is between 1.3577 and 4.6423 minutes shorter than the average committing time for rout B.  

(b) No, because the confidence internal does not contain —5, which corresponds with an average of 5 minutes shorter for route A.

3 0
3 years ago
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