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3 years ago

Write the number 31 in tens and ones. 2 tens

2 answers:

5 0

31 =
3 tens or 30
and 1 ones or 1 and 30 + 1 = 31
"AB84"

sammy [17]3 years ago

3 0

The tens digit of 31 is 3. There are 3 tens in this number and that is equal to 30. Also, the ones digit of this number is equal to 1. The answer to this item are therefore 30 and 1. Hope This Helps! :)

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To find 40% of 75, Priya calculates 2/5⋅75. Does her calculation give the correct value for 40% of 75? Explain how you know.*

Kruka [31]

Answer:

Answer: Yes , priya calculated correctly . The value of 40% of 75 is 30

Step-by-step explanation:

3 0

3 years ago

What is 1 million time 1 billion

Contact [7]

Answer:

1e____ + ___15

4 0

3 years ago

Help me please I beg if you can

Virty [35]

Answer: The mean is 3780

Step-by-step explanation:

Mean is found by adding all values and dividing the sum by how many values were added.

4250+4019+3895+3739+3401+3376=22680
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6 0

3 years ago

the prime factorization of a number is 2 to the power of 3 x 3 to the power of 2 x5 wich statement is true about these factors?

Naddik [55]

Answer:

Fifteen is a factor of the number because both 3 and 5 are prime factors.

Step-by-step explanation:

2^3 * 3^2 * 5

= 2 * 2 * 2 * 3 * 3 * 5

As you can see from, the prime factors are 2, 3, and 5.

3 × 5 = 15, option A is correct.

7 0

3 years ago

Read 2 more answers

Find the surface area of the solid formed by the net. Round your answer to the nearest hundredth.

-BARSIC- [3]

Answer:

<h2>The area of the total figure is around 535.43 square centimeters.</h2>

Step-by-step explanation:

In the image attached, you can notice that all rectangles have a base of 20 centimeters.

Also, each side of the equilaterals triangles is 8 centimeters.

Notice that the height of each rectangle is equal to a side of a triangle.

Using all given vales, the area of each rectangle is

$A_{rectangle}=b\times h=20 \times 8 =160 cm^{2}$

The area of all rectangles is

$A_{rectangles}=3(160cm^{2})=480 cm^{2}$ , because there are three rectangles in total.

The area of each triangle is

$A_{triangle }=\frac{\sqrt{3} }{4} (8cm)^{2} =\frac{\sqrt{3} }{4}(64cm^{2} )\\A_{triangle }=16\sqrt{3} cm^{2}$

The area of both triangles is

$A_{triangles}=2(16\sqrt{3}cm^{2} )=32\sqrt{3} cm ^{2}$

Now, the area of the whole figure is the sum of the area of triangles and rectangles

$A_{total}=480cm^{2} +32\sqrt{3} cm^{2} \approx 535.43 cm^{2}$

Therefore, the area of the total figure is around 535.43 square centimeters.

7 0

3 years ago