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3 years ago

Write the number 31 in tens and ones. 2 tens

2 answers:

5 0

31 =
3 tens or 30
and 1 ones or 1 and 30 + 1 = 31
"AB84"

sammy [17]3 years ago

3 0

The tens digit of 31 is 3. There are 3 tens in this number and that is equal to 30. Also, the ones digit of this number is equal to 1. The answer to this item are therefore 30 and 1. Hope This Helps! :)

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Which one is greater 2/3 or 4/5

Reptile [31]

2/3 because it’s out of 3, if you cut a pizza in 3 slices the slices are bigger and if u take 2 out of the three the remaining piece is bigger than the 4/5 because those 5 pieces will be cut smaller

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3 years ago

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Please help.. I will give points

Daniel [21]

A. 8^9/2= around 11585.2375; (sqrt8)^9= around 11585.2375. So choice A shows a pair of equivalent expressions.

B. (3sqrt125)^9=1,953,125; 125^9/3=1,953,125. So choice B also shows a pair of equivalent expressions.

C. 12^2/7= around 2.03394; (sqrt12)^7= around 5,985.96759. So choice C does not show a pair of equivalent expressions.

D. 4^1/5=around 1.31951; (sqrt4)^5=32. So choice D also doesn't show a pair of equivalent expressions.

Your answers are A and B.

I hope this helps ;)

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3 years ago

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Checks are stale dated when

lina2011 [118]

My guess is before the current date but not sure hope that helped and sorry I could not do more and always good luck

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3 years ago

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If 1 foot 12 inches, which expression can be used to find the

Liono4ka [1.6K]

B is the right awnser

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3 years ago

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Cynthia Besch wants to buy a rug for a room that is 19 ft wide and 32 ft long. She wants to leave a uniform strip of floor aroun

Rainbow [258]

Answer:

The rug should be 15 ft wide and 28 ft long.

Step-by-step explanation:

I have attached a figure that represents the situation.

The the rug is $l$ by $h$ , the width of the strip of floor is $w$ .

We are told that Cynthia can only afford 420 square feet of carpeting; therefore, it must be that

$l*h=420$ (this says the area of the rug must be 420 square feet)

From the figure we see that

$l= 32-2w$

$h=19-2w$

Therefore,

$l*h=420\\\\(32-2w)(19-2w)=420$

We expand this equation and get:

$4w^2-102w+608=420\\\\4w^2-102w+188=0$

using the quadratic equation we get two solutions:

$w=2\\w=23.5$

since the second solution, namely $w=23.5$ , is larger than one of the dimensions of the room (is greater than 19 ft) it cannot be the width of the strip; therefore, we take $w=2$ to be our solution.

Now we find the dimensions of the rug:

$l=32-2(2)=28\\\\h=19-2(2)=15$

The rug is 15 ft wide and 28 ft long.

8 0

3 years ago