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Papessa [141]
3 years ago
7

Which is the equation of a line with a slope of -1/3 and a y-intercept at (0,1)?

Mathematics
2 answers:
Nutka1998 [239]3 years ago
4 0

Answer:

The answer is

\huge \boxed{y =  -  \frac{1}{3}x + 1 }

Step-by-step explanation:

To find an equation of a line given the slope and a point we use the formula

y -  y_1 = m(x -  x_1)

where

m is the slope

( x1 , y1) is the point

From the question the point is (0,1) and slope - 1/3

The equation is

y - 1 =  -  \frac{1}{3}(x - 0) \\ y - 1 =  -  \frac{1}{3} x

We have the final answer as

y =  -  \frac{1}{3} x + 1 \\

Hope this helps you

timama [110]3 years ago
4 0

Answer:

2/3

Step-by-step explanation:

Remember that when you want to write an EQUATION of the line with slope -1/3 and y-intercept (0,1), you can use the "Slope-intercept form" for the equation of the line.

The slope intercept form is: "y =mx+ b"

m is the slope, and b is the y-coordinate of the y-intercept.

For example, m =(-1/3) and b = (1)

Therefore, the equation of the line is

y = (-1/3) + 1

Put (-1/3) + 1 --> into the calculator and you get.....

2/3!!

Hope that helps!

Sydney

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Read 2 more answers
A recent study found that the average length of caterpillars was 2.8 centimeters with a
pogonyaev

Using the normal distribution, it is found that there is a 0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the mean and the standard deviation are given, respectively, by:

\mu = 2.8, \sigma = 0.7.

The probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters is <u>one subtracted by the p-value of Z when X = 4</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{4 - 2.8}{0.7}

Z = 1.71

Z = 1.71 has a p-value of 0.9564.

1 - 0.9564 = 0.0436.

0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

4 0
2 years ago
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