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3 years ago

0 If x and y vary inversely and y=6 as x=7, what is the constant of variation?

Mathematics

1 answer:

gizmo_the_mogwai [7]3 years ago

3 0

Answer:

k = 42

Step-by-step explanation:

given that x and y vary inversely then the equation connecting them is

y = $\frac{k}{x}$ ← k is the constant of variation

To find k use the condition y = 6 when x = 7

k = yx = 6 × 7 = 42

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Describe how you think you can use U.S. traditional multiplication to multiply a 1 digit number by any size number .

egoroff_w [7]

Well for example 4x1=4 hope this helps

8 0

2 years ago

Claire walked her dog 2 1/5 miles. Carson walked her dog 1 3/4 times as far as Claire did. How many more miles did Carson walk h

Anon25 [30]

The word "times" means you have to multiply.

2 1/5 times 1 3/4 is 3 17/20.

The phrase "how many more" means you have to subtract.

3 17/20 minus 2 1/5 is 1 13/20.

Carson walked her dog 1 13/20 more miles than Claire did.

Sorry for the lazy explanations Imao

6 0

2 years ago

Can you solve 27,28,39,30,31,32,33,34?

kozerog [31]

Answer:

27. x^7

28. 4x^13

29. 1/f^4

30. x^5

31. 2x^14

32. (4y^3 x^2)^2

33. (2y/x)^6

Step-by-step explanation:

$27. \: \: \frac{ {x}^{ - 1} }{ {x}^{ - 8} } \\ \frac{ {x}^{8} }{ {x}^{1} } \\ {x}^{8 - 1} = {x}^{7} \\$

$28. \: \: \: \frac{ {52x}^{6} }{ {13x}^{ - 7} } \\ \frac{ {52x}^{6} {x}^{7} }{13} \\ {4x}^{6 + 7} = {4x}^{13}$

$29. \: \: {f}^{ - 3} ( {f}^{2} )( {f}^{ - 3} ) \\ {f}^{( - 3) +2 + ( - 3) } \\ {f}^{ - 4} \\ \frac{1}{ {f}^{4} } \\$

$30. \: \: \frac{ {x}^{ - 4} }{ {x}^{ - 9} } \\ \frac{ {x}^{9} }{ {x}^{4} } \\ {x}^{9 - 4} = {x}^{5}$

$31. \: \: \frac{ {24x}^{6} }{ {12x}^{ - 8} } \\ \frac{ {24x}^{6} {x}^{8} }{12} \\ {2x}^{6 + 8} = {2x}^{14} \\$

$32. \: \: \frac{ {3x}^{2} {y}^{ - 3} }{ {12x}^{6} {y}^{3} } \\ \frac{ {3x}^{2} }{ {12x}^{6} {y}^{3} {y}^{3} } \\ \frac{ {x}^{2 - 6} }{ {4y}^{3 + 3} } \\ \frac{ {x}^{ - 4} }{ {4y}^{6} } \\ \frac{1}{ {4y}^{6} {x}^{4} } = \frac{1}{({ {4y}^{3} {x}^{2} ) }^{2} }$

$33. \: \: {( {2x}^{3} {y}^{ - 3}) }^{ - 2} \\ {2x}^{3 \times - 2} {y}^{ - 3 \times - 2} \\ {2x}^{ - 6} {y}^{6} \\ \frac{ {2y}^{6} }{ {x}^{6} } \\ {( \frac{2y}{x} )}^{6} \\$

4 0

2 years ago

Find the value of given expression <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B645%20%5Ctimes%20645%7D%20" id="TexForm

Sergio039 [100]

$208012.5$

Step-by-step explanation:

$\sqrt{645 \times 645}$

$= \sqrt{416025}$

$= 208012.5$

3 0

2 years ago

Read 2 more answers

The reading speed of sixth-grade students is approximately normal, with a mean speed of 125 words per minute and a standard devi

Lisa [10]

Answer:

Part A

μ of the reading speed of sixth-grade students = 125 words

σ of the reading speed of sixth-grade students = 24 words

Part B

The probability that a randomly selected sixth-grade student reads less than 100 words per minute is 14.92%

Part C

The probability that a randomly selected sixth-grade student reads more than 140 words per minute is 26.43%

Step-by-step explanation:

Part A:

μ of the reading speed of sixth-grade students = 125 words

σ of the reading speed of sixth-grade students = 24 words

Part B:

1. Let's find the z-score for a randomly selected sixth-grade student that reads less than 100 words per minute:

z-score = (100 - 125)/24

z-score = -25/24

z-score = -1.04

2. Now, let's find out the probability that a randomly selected sixth-grade student that reads less than 100 words per minute, using the z-table:

P (-1.04) = 0.1492

This means that the probability that a randomly selected sixth-grade student that reads less than 100 words per minute is 14.92%

Part C.

1. Let's find the z-score for a randomly selected sixth-grade student that reads more than 140 words per minute:

z-score = (140 - 125)/24

z-score = 15/24

z-score = 0.63

2. Now, let's find out the probability that a randomly selected sixth-grade student that reads more than 140 words per minute, using the z-table:

P (0.63) = 0.7357

But we're being asked for a randomly selected student that reads more than 140 words, then:

1 - P(0.63) = 1 - 0.7357 = 0.2643

This means that the probability that a randomly selected sixth-grade student that reads more than 140 words per minute is 26.43%

8 0

3 years ago