0 If x and y vary inversely and y=6 as x=7, what is the constant of variation?

Y-6=4(x+5) what are the Y and X intercept

Misha Larkins [42]

Hello.

Reorder the terms: -6 + y = 4(x + 5)

Reorder the terms: -6 + y = 4(5 + x) -6 + y = (5 * 4 + x * 4) -6 + y = (20 + 4x)

Solving -6 + y = 20 + 4x Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '6' to each side of the equation. -6 + 6 + y = 20 + 6 + 4x

Combine like terms: -6 + 6 = 0 0 + y = 20 + 6 + 4x y = 20 + 6 + 4x

Combine like terms: 20 + 6 = 26 y = 26 + 4x

Simplifying y = 26 + 4x

x-intercept: (−132,0)(-132,0)y-intercept: (0,26)

Have a nice day

4 0

3 years ago

Evaluate (x-a+3) if the value of x is (a+7).

Nikitich [7]

Answer:

3(x - a)(x - b)(x - c) when a + b + c = 3x .

Step-by-step explanation:

i don't know but this has to be right

4 0

3 years ago

Someone pls help me ill give out brainliest pls don’t answer if you don’t know

iren [92.7K]

Answer:

Step-by-step explanation:

The area of a sector has the formula

$A_s=\frac{\theta}{360}*\pi r^2$ Hopefully, this looks somewhat familiar to you. Theta is the central angle given as 75, r is the radius given as 4. Filling in:

$A_s=\frac{75}{360}*(3.14)(4)^2$ and simplifying that a bit to look less threatening, but not by much:

$A_s=\frac{5}{24}(3.14)(16)$ and

$A_s=\frac{251.2}{24}=\frac{157}{15}=10.466666666...$ Not sure how you're supposed to express your answer so I gave both the fraction and its decimal equivalency.

8 0

3 years ago

A medical researcher wondered if there is a significant difference between the mean birth weight of boy and girl babies. Random

Yuliya22 [10]

Answer:

b) independent samples t-test

$t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154$

$p_v =2*P(t_{8}>0.154) =0.881$

So with the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).

Step-by-step explanation:

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 = \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

Or equivalently:

Null hypothesis: $\mu_1 - \mu_2 = 0$

Alternative hypothesis: $\mu_1 -\mu_2\neq 0$

Our notation on this case :

$n_1 =5$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

We can calculate the mean and deviation for eaach group with the following formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X_1 =5.92$ represent the sample mean for the group 1

$\bar X_2 =5.74$ represent the sample mean for the group 2

$s_1=1.88$ represent the sample standard deviation for group 1

$s_2=1.81$ represent the sample standard deviation for group 2

If we see the alternative hypothesis we see that we are conducting a bilateral test and with independnet samples t test.

b) independent samples t-test

The statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{S^2_2}{n_2}}$

And now we can calculate the statistic:

$t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154$

The degrees of freedom are given by:

$df=5+5-2=8$

And now we can calculate the p value using the altenative hypothesis:

$p_v =2*P(t_{8}>0.154) =0.881$

So with the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).

7 0

3 years ago

8 tins holds 42-2-3 liter of oil. How many liters can 1such tin hold

GarryVolchara [31]

Answer = 4.625

Solution =42-2-3=37

37 divided by 8 = 4.625

Holley Gus’s it’s the answer

8 0

3 years ago