Answer: x=55 y=145
x=55
35+90=125
125-180=55
y=145
180-35=145
I hope this is good enough:
<span>Given the quadratic equation: f(x) = -2x^2 - 2x - 1, the axis of symmetry can be obtained by finding the line that divides the function into two congruent or identical halves. Thus, it should pass through the vertex and is equal
to the x-coordinate of the vertex. </span>
<span>Note that a quadratic
equation in standard form: y = ax^2 + bx + c, has the vertex located at (h,k) where, h = -b/2a and k is determined by evaluating y at
h. In this case, a = -2, b = -2, thus, h = -0.5, k = 0.5. Thus, the vertex is located at (-0.5, 0.5) and the axis of symmetry is at x = -0.5. </span>
Answer:
Step-by-step explanation:
(2x + 1)(ax + b) = 6x² - 5x + c
Expand the left side and put that half into standard form:
2ax² + 2bx + ax + b = 6x² - 5x + c
2ax² + (2b + a)x + b = 6x² - 5x + c
So now look at the x terms. We have "2a" x² on left and 6 x² on right, so:
2a = 6
a = 3
Then look at the x terms, those coefficients will then be equal:
2b + a = -5
2b + 3 = -5
2b = -8
b = -4
and finally, then non-x terms are equal:
b = c
-4 = c
so:
a = 3, b = -4, c = -4
