Given:
Principal = $14000
Rate of interest = 10% compounded semiannually.
Time = 11 years.
To find:
The accumulated value of the given investment.
Solution:
Formula for amount or accumulated value after compound interest is:
![A=P\left(1+\dfrac{r}{n}\right)^{nt}](https://tex.z-dn.net/?f=A%3DP%5Cleft%281%2B%5Cdfrac%7Br%7D%7Bn%7D%5Cright%29%5E%7Bnt%7D)
Where, P is the principal values, r is the rate of interest in decimal, n is the number of times interest compounded in an year and t is the number of years.
Compounded semiannually means interest compounded 2 times in an years.
Putting
in the above formula, we get
![A=14000\left(1+\dfrac{0.10}{2}\right)^{2(11)}](https://tex.z-dn.net/?f=A%3D14000%5Cleft%281%2B%5Cdfrac%7B0.10%7D%7B2%7D%5Cright%29%5E%7B2%2811%29%7D)
![A=14000\left(1+0.05\right)^{22}](https://tex.z-dn.net/?f=A%3D14000%5Cleft%281%2B0.05%5Cright%29%5E%7B22%7D)
![A=14000\left(1.05\right)^{22}](https://tex.z-dn.net/?f=A%3D14000%5Cleft%281.05%5Cright%29%5E%7B22%7D)
![A\approx 40953.65](https://tex.z-dn.net/?f=A%5Capprox%2040953.65)
Therefore, the accumulated value of the given investment is $40953.65.
21k - 3n + 9p > 3p + 12....for n
-3n > 3p + 12 - 9p - 21k
n < (3p + 12 - 9p - 21k) / -3
n < -p - 4 + 3p + 7k
n < 2p - 4 + 7k <===
Answer:
47
Step-by-step explanation:
www.alcula.com/calculators/statistics/median/
Answer:
X > -4
Step-by-step explanation:
Collect the like terms which literally leaves you with -x<4
Then just changes the signs, hence the answer.
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