Answer:
computer works on electricity
Explanation:
 
        
             
        
        
        
Answer:An initial condition is an extra bit of information about a differential equation that tells you the value of the function at a particular point. Differential equations with initial conditions are commonly called initial value problems.
The video above uses the example
{
d
y
d
x
=
cos
(
x
)
y
(
0
)
=
−
1
to illustrate a simple initial value problem. Solving the differential equation without the initial condition gives you  
y
=
sin
(
x
)
+
C
.
Once you get the general solution, you can use the initial value to find a particular solution which satisfies the problem. In this case, plugging in  
0
 for  
x
 and  
−
1
 for  
y
 gives us  
−
1
=
C
, meaning that the particular solution must be  
y
=
sin
(
x
)
−
1
.
So the general way to solve initial value problems is: - First, find the general solution while ignoring the initial condition. - Then, use the initial condition to plug in values and find a particular solution.
Two additional things to keep in mind: First, the initial value doesn't necessarily have to just be  
y
-values. Higher-order equations might have an initial value for both  
y
 and  
y
′
, for example.
Second, an initial value problem doesn't always have a unique solution. It's possible for an initial value problem to have multiple solutions, or even no solution at all.
Explanation:
 
        
             
        
        
        
C - An Intranet will give access to all employees within the company, whether they work from home or at the office.
        
                    
             
        
        
        
Answer:
class Db_test(models.Model):
    name = models.CharField(max_length=50)
    comment = models.CharField(max_length=200)
    created = models.DateField(auto_now_add=True)
    modified = models.DateField(auto_now=True)
    class Meta:
        db_table = "db_test"
Explanation:
 
        
             
        
        
        
Answer:
True
Explanation:
for loop is used to repeat the process again and again until the condition not failed.
syntax:
for(initialize; condition; increment/decrement)
{
     Statement
} 
But we can omit the initialize or condition or increment/decrement as well
the syntax after omit the initialization,
for( ; condition; increment/decrement)
{
     Statement
} 
The above for loop is valid, it has no error.
Note: don't remove the semicolon.
You can omit the condition and  increment/decrement.
and place the semicolon as it is. If you remove the semicolon, then the compiler show syntax error.