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AnnyKZ [126]
3 years ago
10

What does the group on option do?

Computers and Technology
1 answer:
luda_lava [24]3 years ago
5 0

Answer:

D. allows you to add calculations

Explanation:

GROUP ON is a database function that allows you to group together a series of results sharing common values for the indicated fields.  That allows you to add calculations.

You could for example, count how many students are in Mrs Brown's class, or how many of them had a grade of 80% or more on the last test.  Or instantly calculate the class' average for every teacher in the school, maybe grouped by teacher/level, and so on.

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Convert<br> 0.625 to binary
Anastaziya [24]

\huge{ \rm{Question:}}

Convert

0.625 to binary

\huge{ \rm{Answer:}}

Translate 0.625 into a fraction. We all know that 0.5 is ½. We know that the remainder, 0.125, is ⅛. Add them together, and you get ½ + ⅛ = ⅝.

Now, in binary, the positions to the right of the point are , which is ½, ¼, and ⅛ respectively.

⅝ is 5 × ⅛. 5 in binary is 101. So, ⅝ is

= 0.101

8 0
2 years ago
Consider a set of mobile computing clients in a certain town who each
poizon [28]

Answer: answer given in the explanation

Explanation:

We have n clients and k-base stations, say each client has to be connected to a base station that is located at a distance say 'r'. now the base stations doesn't have allocation for more than L clients.

To begin, let us produce a network which consists of edges and vertex

Network (N) = (V,E)

where V = [S, cl-l, - - - -  cl-n, bs-l - - - - - - bs-k, t]

given that cl-l, - - - - - cl-n represents nodes for the clients

also we have that bs-l, - - - - - bs-k represents the nodes for base station

Also

E = [ (s, cl-i), (cl-i,bs-j), (bs-j,t)]

(s, cl-i) = have capacity for all cl-i (clients)

(cl-i,bs-j) = have capacity for all cl-i  clients & bs-j (stations)

⇒ using Fond Fulkorson algorithm we  find the max flow in N

⇒ connecting cl-i clients to  bs-j stations

      like (cl-i, bs-j) = 1

   if f(cl-i, bs-j)  = 0

⇒ say any connection were to produce a valid flow, then

if cl-i (clients) connected                f(s,cl-i) = 1 (o otherwise)

if cl-i (clients) connected  to bs-j(stations)   f(cl-i,bs-j) = 1 (o otherwise)

   f(bs-j,t) = no of clients  (cl-i)  connected to bs-j

⇒ on each node, the max flow value (f) is longer than the no of clients that can be connected.

⇒ create the connection between the client and base station i.e. cl-l to base bs-j iff    f(cl-i, bs-j) = 1

⇒ when considering the capacity, we see that any client cannot directly connect to the base stations, and also the base stations cannot handle more than L clients, that is because the load allocated to the base statsion is L.

from this, we say f is the max no of clients (cl-i) that can be connected if we find the max flow, we can thus connect the client to the base stations easily.

cheers i hope this helps

5 0
3 years ago
Explain the principles of computer applications ​
9966 [12]

Answer:

The nature of computers and code, what they can and cannot do.

How computer hardware works: chips, cpu, memory, disk.

Necessary jargon: bits, bytes, megabytes, gigabytes.

How software works: what is a program, what is "running"

How digital images work.

Computer code: loops and logic.

Big ideas: abstraction, logic, bugs.

3 0
3 years ago
Write a definition in your own words for Raster Graphic. Do not copy and paste please.
Vlada [557]

Answer:

Raster Graphic is a bitmap. They are basically a grid of small pixels that make an image.

6 0
3 years ago
Desinated for a network connection within a largecity or multiple small citys
frozen [14]

I think it is WAN (Wide Area Network).

6 0
3 years ago
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