Question

A line that includes the points (6,h) and (7,−10) has a slope of −7. ​ ​ What is the value of h ? ​

Answer 1

Answer:

the answer is h= -3

Step-by-step explanation:

add 7 to -10 to find the value of h

Answer 2

Answer:

-3

Step-by-step explanation:

You can use $\frac{y_2-y_1}{x_2-x_1}$ to find the slope of a line going through $(x_1,y_1)$ and $(x_2,y_2)$.

I like to line up the points and subtract vertically. Then put 2nd difference over 1st difference.

(6,h)

minus

(7,-10)

------------

-1     h-(-10)

$\frac{h-(-10)}{-1}$

This also said to be equal to -7:

$\frac{h+10}{-1}=-7$

Multiply -1 on both sides:

$h+10=7$

Subtract 10 on both sides:

$h=7-10$

[texh=-3[/tex]

So if h=-3 then the slope of the line going through (6,h) and (7,-10) is -7.

Let's test it:

(6,-3)

minus

(7,-10)

----------

-1  7

So the slope is 7/-1=-7. This is the intended goal.

The check is good.