Answer:
-3
Step-by-step explanation:
You can use
to find the slope of a line going through
and
.
I like to line up the points and subtract vertically. Then put 2nd difference over 1st difference.
(6,h)
minus
(7,-10)
------------
-1 h-(-10)
![\frac{h-(-10)}{-1}](https://tex.z-dn.net/?f=%5Cfrac%7Bh-%28-10%29%7D%7B-1%7D)
This also said to be equal to -7:
![\frac{h+10}{-1}=-7](https://tex.z-dn.net/?f=%5Cfrac%7Bh%2B10%7D%7B-1%7D%3D-7)
Multiply -1 on both sides:
![h+10=7](https://tex.z-dn.net/?f=h%2B10%3D7)
Subtract 10 on both sides:
![h=7-10](https://tex.z-dn.net/?f=h%3D7-10)
[texh=-3[/tex]
So if h=-3 then the slope of the line going through (6,h) and (7,-10) is -7.
Let's test it:
(6,-3)
minus
(7,-10)
----------
-1 7
So the slope is 7/-1=-7. This is the intended goal.
The check is good.