The sum is 15 but not sure on how to do the rest though i hope it helps!
Answers: Using the process of completing the square:
1. Isolate the constant by <u>adding 7 to</u> both sides of the equation:
x^2-6x-7+7=0+7
x^2-6x=7
2. Add <u>9</u> to both sides of x2 – 6x = 7 to form a perfect square trinomial while keeping the equation balanced:
x^2-6x+9=7+9
x^2-6x+9=16
3. Write the trinomial x2 – 6x + 9 as squared:
<u>(x-3)^2</u> = 16
4. Use the square root property of equality to get x – 3 = ±<u>4</u> .
sqrt[ (x-3)^2 ] = ± sqrt(16)
x-3 = ±4
5. Isolate the variable to get solutions of –1 and 7.
x-3 = ±4
x-3+3 = ±4+3
x = ±4+3
x1=-4+3→x1=-1
x2=+4+3→x2=7
Answer:
2/3, 5/7, 16/12
From least to greatest!
Smallest = 2/3, Second = 5/7, Largest = 16/12
Hope this helped :-)
Answer:
-4.5
Step-by-step explanation:
