Answer:
The approximated value of JK is 10.6 cm answer (A)
Step-by-step explanation:
∵ JI // KH // LG
∵ XI and XJ are two transversal
∴ 
∵ LK = 18 cm , GH = 22 cm and HI = 13 cm
∴ 
∴ KJ = (13)(18) ÷ 22 = 10.6363 cm
∴ The approximated value of JK is 10.6 cm
<span> (6y^2 + 4y + 5) – (3 – 7y + y^2)
= </span><span> 6y^2 + 4y + 5 – 3 + 7y - y^2
= 5</span>y^2 + 11y + 2
hope it helps
Answer:
Step-by-step explanation:
p = (1/r) - q
In order to find this, follow the order of operations to get the answer.
1/p+q = r ----> Multiply both sides by p+q
1 = r(p + q) -----> Divide by r
1/r = p + q -----> subtract q from both sides
(1/r) - q = p
Answer:
[-16,-4]
Step-by-step explanation:
We are given that
Domain=[-2,1]
We have to find the set of range values of f(x).
Substitute x=-2
Substitute x=1
Range of f(x)=[-16,-4]
Hence, the set of range values of f(x)
[-16,-4]
