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Katena32 [7]
3 years ago
9

Find 250% of 800How did you work the problem out?!!

Mathematics
2 answers:
baherus [9]3 years ago
4 0
Find 100% which is 800

100% (800) X2= 1600

Find 50% of 800 which is 400

1600+400=2000

OR

250%=2.5 in decimals

800X2.5=2000
zaharov [31]3 years ago
3 0
250% is 2.5 multiply 800 by 2.5 and you should get 2000
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a math test has 25 questions on it if a student incorrectly answers 5 questions on the test what percentage of problems are corr
ikadub [295]

The student would get an 80%.

Since 5 is 20% of 25, subtract 20 from 100 and you get 80%

7 0
3 years ago
Select all of the choices that are equal to (-5) - (-12)<br><br> -7<br> 7<br> (-5)+12<br> (-5)+(-12)
Roman55 [17]

Answer:

the awnser is. (-5) + (-12)

7 0
3 years ago
Read 2 more answers
What is this simplified? Please help
Naya [18.7K]

Answer:

The end result is -1/(x + 1)

Step-by-step explanation:

In order to find the answer to this, we first need to factor the denominator. Since it is a quadratic, we try to find number that multiply to the last term (8) and add to the middle term (9). In this case, the numbers 8 and 1 would work. This allows us to use those numbers in parenthesis along with x as a fully factored form.

x^2 + 9x + 8 = (x + 1)(x + 8)

Now that we have this factored we can take the original equation and factor a -1 out of the top.

(-1)(x + 8)/(x + 1)(x + 8)

Since there is an (x + 8) on the top and bottom, we can cancel those.

-1/(x + 1)

6 0
3 years ago
Please find the area<br> 420ft2<br><br> 210ft2
Minchanka [31]

Answer:

Area= L×B

Area=420ft²×210ft²

Area=88200ft²

7 0
3 years ago
A metallurgist has an alloy with 5% titanium and an alloy with 30% titanium. He needs 100 grams of an alloy with 15% titanium. H
andrey2020 [161]
Let us convert the percentages to decimal format first.. so 5% is just 5/100 or 0.05 and 15% is just 15/100 or 0.15

so hmmm, so, let's say it needs "x" amount and "y" amount of each respectively, so, whatever "x" and "y" are, they must add up to 100, and whatever their concentration is, must add up to what the mixture yields

thus

\bf \begin{array}{lccclll}&#10;&amount&concentration&&#10;\begin{array}{llll}&#10;concentrated\\&#10;amount&#10;\end{array}\\&#10;&-----&-------&-------\\&#10;\textit{5\% alloy}&x&0.05&0.05x\\&#10;\textit{30\% alloy}&y&0.30&0.3y\\&#10;-----&-----&-------&-------\\&#10;mixture&100&0.15&15&#10;\end{array}&#10;\\\\\\&#10;\begin{cases}&#10;x+y=100\implies \boxed{y}=100-x\\&#10;0.05x+0.3y=15\\&#10;----------\\&#10;0.5x+0.3\left( \boxed{100-x} \right)=15&#10;\end{cases}

solve for "x"

what's "y"? well, y = 100 - x
4 0
3 years ago
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