1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alex17521 [72]
3 years ago
15

Evaluate x^0+ y^0 for x = 3 and y = 2. 0 1 5 2

Mathematics
1 answer:
stiks02 [169]3 years ago
5 0

Answer:

2

Step-by-step explanation:

x^0+ y^0

Let x = 3 and y = 2

3^0 + 2^0

Raised to the 0 power is 1

1 + 1

2

You might be interested in
How to work vector algebra
erica [24]

Vectors and vector addition:

A scalar is a quantity like mass or temperature that only has a magnitude. On the other had, a vector is a mathematical object that has magnitude and direction. A line of given length and pointing along a given direction, such as an arrow, is the typical representation of a vector. Typical notation to designate a vector is a boldfaced character, a character with and arrow on it, or a character with a line under it (i.e., ). The magnitude of a vector is its length and is normally denoted by or A.  Addition of two vectors is accomplished by laying the vectors head to tail in sequence to create a triangle such as is shown in the figure.  The following rules apply in vector algebra.where P and Q are vectors and a is a scalar. 

Unit vectors:

A unit vector is a vector of unit length. A unit vector is sometimes denoted by replacing the arrow on a vector with a "^" or just adding a "^" on a boldfaced character (i.e., ). Therefore, Any vector can be made into a unit vector by dividing it by its length. Any vector can be fully represented by providing its magnitude and a unit vector along its direction.

Base vectors and vector components:

Base vectors are a set of vectors selected as a base to represent all other vectors. The idea is to construct each vector from the addition of vectors along the base directions. For example, the vector in the figure can be written as the sum of the three vectors u1, u2, and u3, each along the direction of one of the base vectors e1, e2, and e3, so that Each one of the vectors u1, u2, and u3 is parallel to one of the base vectors and can be written as scalar multiple of that base. Let u1, u2, and u3 denote these scalar multipliers such that one has<span> </span><span>The original vector</span><span> </span><span>u</span><span> </span><span>can now be written as </span><span>The scalar multipliers</span><span> </span><span>u</span><span>1</span><span>,</span><span> </span><span>u</span><span>2</span><span>, and</span><span> </span><span>u</span><span>3</span><span> </span><span>are known as the components of</span><span> </span><span>u</span><span> </span><span>in the base described by the base vectors</span><span> </span><span>e</span><span>1</span><span>,</span><span> </span><span>e</span><span>2</span><span>, and</span><span> </span><span>e</span><span>3</span><span>. If the base vectors are unit vectors, then the components represent the lengths, respectively, of the three vectors</span><span> </span><span>u</span><span>1</span><span>,</span><span> </span><span>u</span><span>2</span><span>, and</span><span> </span><span>u</span><span>3</span><span>. If the base vectors are unit vectors and are mutually orthogonal, then the base is known as an orthonormal, Euclidean, or Cartesian base.</span>

 

A vector can be resolved along any two directions in a plane containing it. The figure shows how the parallelogram rule is used to construct vectors a and b that add up to c. <span>In three dimensions, a vector can be resolved along any three non-coplanar lines. The figure shows how a vector can be resolved along the three directions by first finding a vector in the plane of two of the directions and then resolving this new vector along the two directions in the plane. </span><span>When vectors are represented in terms of base vectors and components, addition of two vectors results in the addition of the components of the vectors.</span>

8 0
3 years ago
Read 2 more answers
What is the ratio of our solar system's radius to the Milky Way's radius given that the distance from Pluto to the sun is 5.9 *
kherson [118]

Answer:

Just divide the sun-pluto distance by the milky way radius and you get the following ratio:

6.6 x 10^7 : 1

7 0
3 years ago
Syd chooses two different primes, both of which are greater than $10,$ and multiplies them. The resulting product is less than $
Mars2501 [29]

Answer:

  10

Step-by-step explanation:

There are 7 primes between 10 and 35: 11, 13, 17, 19, 23, 29, 31.

The product of 11 and any of the others will be less than 350, 6 products.

The product of 13 and any below 26 will be less than 350, 3 more products.

The product of 17 and any below 20 will be less than 350, 1 more product.

There are a total of 10 different products below 350 possible.

_____

11·13, 11·17, 11·19, 11·23, 11·29, 11·31, 13·17, 13·19, 13·23, 17·19

6 0
4 years ago
Find the area of a triangle measuring 25 feet long by 8 feet wide
nata0808 [166]
Triangle area= b*h/2

Plug in the values:
25*8/2
200/2
100

Final answer: 100 ft^2
5 0
3 years ago
state whether the lines represented by the equations y=1/2x-1 and y+4=-1/2(x-2) are paraller, perdendicular, or neither
Brrunno [24]
The easiest way to tell whether lines are parallel, perpendicular, or neither is when they are written in slope-intercept form or y = mx + b. We will begin by putting both of our equations into this format.

The first equation, y =  \frac{1}{2}x - 1 is already in slope intercept form. The slope is 1/2 and the y-intercept is -1.

The second equation requires rearranging.
y + 4 =  -\frac{1}{2}(x - 2) \\ y + 4 = -\frac{1}{2}x + 1 \\ y = - \frac{1}{2} x- 3
From this equation, we can see that the slope is -1/2 and the y-intercept is -3.

When lines are parallel, they have the same slope. This is not the case with these lines because one has slope of 1/2 and the other has slope of -1/2. Since these are not the same our lines are not parallel.

When lines are perpendicular, the slope of one is the negative reciprocal of the other. That is, if one had slope 2, the other would have slope -1/2. This also is not the case in this problem.

Thus, we conclude that the lines are neither parallel nor perpendicular.
8 0
4 years ago
Other questions:
  • How to solve? Sarah has a $100 she gave 3/4 of the money to her sister. She gave a 1/2 of the rest of the money to her friend. H
    13·1 answer
  • In the set of ordered pairs {(1, 3), (-6, 0), (3, 11)}, the range is:
    5·2 answers
  • A highway had a landslide, where 3,000 cubic yards of material fell on the road, requiring 200 dump truck loads to clear. On ano
    7·1 answer
  • What is the mean score for Mr. Wilson's test scores? Round to the nearest tenth.
    11·2 answers
  • What is the coefficient in the inequality 3x=10?
    8·1 answer
  • What is the Y intercept of the graph of the following linear equation 3X -3 equals Y! BRAIIEST
    11·2 answers
  • Sam deposited $400 into her savings account that earned 4.5% interest per year. How much money did she have after 2.5 years?
    15·1 answer
  • A boat traveled 308 miles each way downstream and back. The trip downstream took 11 hours. The trip back took 22 hours. Find the
    5·1 answer
  • I need help on number 19 and 20
    10·2 answers
  • Find the 8th term of the geometric sequence shown below. 6x,18x^4,54x^7<br> please help
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!