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3 years ago

Eureka math grade 7 module 6 lesson 23 problem set

Mathematics

2 answers:

andre [41]3 years ago

6 0

Answer:

Step-by-step explanation:

erastova [34]3 years ago

4 0

It’s whatever Jeremy or however you spell his name said

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Beth borrowed $13,000 at 12% simple interest for 1.75 years. How much interest did she have to pay?

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The interest is: $2730.00

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I used a calculator

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3 years ago

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5.If the median annual salary for 4 employees is $60,000, then which of the following must be true? A. 2 people earn $60,000 a y

Reika [66]

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Hope this helps! :)

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3 years ago

Consider a relatively simple healu insurance plan with the

notka56 [123]

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3 years ago

Kelly has 1/2 of a gallon of milk left in her refrigerator. She drank 3/4 of it. What fraction of gallon of milk is left in the

Colt1911 [192]

1/4
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3 years ago

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PLLLLEEEEEEAAASSSSSSSSEEEE

mrs_skeptik [129]

Given:

Line a passes through (2, 10) and (4, 13).

Line b passes through (4, 9) and (6, 12).

Line c passes through (2, 10) and (4, 9).

To find:

Which of the lines, if any are perpendicular.

Solution:

If a line passes through two points, then the slope of line is

$m=\dfrac{y_2-y_1}{x_2-x_1}$

Line a passes through (2, 10) and (4, 13). So, slope of this line is

$m_a=\dfrac{13-10}{4-2}=\dfrac{3}{2}$

Line b passes through (4, 9) and (6, 12). So, slope of this line is

$m_b=\dfrac{12-9}{6-4}=\dfrac{3}{2}$

Line c passes through (2, 10) and (4,9). So, slope of this line is

$m_c=\dfrac{9-10}{4-2}=\dfrac{-1}{2}$

Product of slopes of to perpendicular lines is -1.

$m_a\cdot m_b=\dfrac{3}{2}\times \dfrac{3}{2}=\dfrac{9}{4}\neq -1$

$m_b\cdot m_c=\dfrac{3}{2}\times \dfrac{-1}{2}=\dfrac{-3}{4}\neq -1$

$m_a\cdot m_c=\dfrac{3}{2}\times \dfrac{-1}{2}=\dfrac{-3}{4}\neq -1$

Therefore, any of these lines are not perpendicular to each other.

8 0

3 years ago