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4 years ago

Question 18 of 20

Computers and Technology

2 answers:

olga2289 [7]4 years ago

5 0

Answer:

B. Worked as a sales associate for two years -Apex

Explanation:

Anon25 [30]4 years ago

3 0

Answer:

It's B

Explanation:

His 2 years of working as a sales associate is the most experience like thing on this list (APEX)

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Curtis has been testing a new software package for the past two months. However, he decides not to switch and goes back to using

hodyreva [135]

Retro-active interference

8 0

4 years ago

Write a script that calculates the common factors between 8 and 24. To find a common factor, you can use the modulo operator (%)

AnnyKZ [126]

Answer:

common = []
num1 = 8
num2 = 24
for i in range(1, num1 + 1):
if(num1 % i == 0 and num2 % i == 0):
common.append(i)
print(common)

Explanation:

The solution is written in Python 3.

Firstly create a common list to hold a list of the common factor between 8 and 24 (Line 1).

Create two variables num1, and num2 and set 8 and 24 as their values, respectively (Line 3 - 4).

Create a for loop to traverse through the number from 1 to 8 and use modulus operator to check if num1 and num2 are divisible by current i value. If so the remainder of both num1%i and num2%i will be zero and the if block will run to append the current i value to common list (Line 6-8).

After the loop, print the common list and we shall get [1, 2, 4, 8]

8 0

3 years ago

Convert the following numbers. (Please show all steps; no marks will be awarded if no steps are shown) [1.5 x 4 = 6 marks]

katen-ka-za [31]

Answer:

i. 10210212

ii. 100 101 001 in BASE 2

iii. 46.4631

iv. 12.453125

Explanation:

i. Converting to base 10 we get

= 10 x 162 + 13 x 161 + 9 x 160 = 2777

Converting to base 10 we get =

2777/3 = 925 with remainder 2

925/3 = 308 with remainder 1

308/3 = 102 with remainder 2

102/3 = 34 with remainder 0

34/3 = 11 with remainder 1

11/3 = 3 with remainder 2

3/3 = 1 with remainder 0

1/3 = 0 with remainder 1

Hence the Answer is 10210212

ii. = Octal is taken in pair of 3 bits , Writing binary of each number in 3 bits we get = 100 101 001 in BASE 2

iii. = 1 x 52 + 2 x 51 + 3 x 50 + 3 x 5-1 = 38.6 in decimal

Converting to Octal we get

38 /8 = 4 with remainder 6

4 /8 = 0 with remainder 4

.6 x 8 = 4.8

.8 x 8 = 6.4

46.4631

iv. = 1x 81 + 4 x 80 + 3 x 8-1 + 5 x 8-2 = 12.453125

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4 0

3 years ago

Write one for loop to print out each element of the list several things. then write another for loop

Kay [80]

Question:

Write one for loop to print out each element of the list several_things. Then, write another for loop to print out the TYPE of each element of the list several_things.

Answer:

The solution in python is as follows:

for element in several_things:

print(element)

for element in several_things:

print(type(element))

Explanation:

The solution assumes that the list several_things has already been initialized.

So, the rest of the code is explained as follows:

This line iterates through the list, several_things

for element in several_things:

This line prints each element

print(element)

This line iterates through the list, several_things for the second time

for element in several_things:

This line prints the type of each element

print(type(element))

6 0

3 years ago

Help guys thank you =)

MrRissso [65]

1.LR
2.LR
3.HR
4.LR
5.HR

6 0

3 years ago