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sashaice [31]
3 years ago
10

the number of grams a woman should eat in a day to maintain her weight is proportional to her weight. a woman weighing 102 pound

s should eat only 34 grams of fat in a day to maintain her weight, at this rate how many grams of fat should a woman that weighs 180 pounds eat in a day to maintain her weight
Mathematics
1 answer:
vitfil [10]3 years ago
7 0
Given:
grams of fat : 34 grams TO weight of woman : 102 pounds
grams of fat : ? TO weight of woman : 180 pounds

This is a proportion problem: 34 grams to 102 pounds.

We first have to convert a unit of measure to another to maintain uniformity of measure. let us convert pounds to grams:

102 pounds * 453.592 grams / pound = 46,266.384 grams
180 pounds * 453.592 grams / pound = 81,646.560 grams

34 grams to 46,266.384 grams = x grams to 81,646.560 grams

proportion: a:b = c:d where ad = bc

34 grams * 81,646.560 grams = x * 46,266.384 grams
2,775,983.04 grams² = x * 46,266.384 grams
2,775,983.04 grams² ÷ 46,266.384 grams = x
60 grams = x 

A woman weighing 180 pounds should eat 60 grams of fat to maintain her weight.
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Answer:

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Step-by-step explanation:

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in our case:

7\angle\dfrac{3\pi}{4}

to covert the polar to cartesian:

x = r\cos{\theta}

y = r\sin{\theta}

we can plug in our values:

x = 7\cos{\dfrac{3\pi}{4}} = -7\dfrac{\sqrt{2}}{2}

y = 7\sin{\dfrac{3\pi}{4}} = 7\dfrac{\sqrt{2}}{2}

the Cartesian coordinates are:

\left(x,y\right)=\left(-7\dfrac{\sqrt{2}}{2},7\dfrac{\sqrt{2}}{2}\right)

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(b) to convert (x,y) = (6.06,-3.5)

we'll use the pythagoras theorem to find 'r'

r^2 = x^2+y^2

r^2 = (6.06)^2+(-3.5)^2

r = \sqrt{48.97} \approx 7

the angle can be found by:

\tan{\theta} = \dfrac{y}{x}

\tan{\theta} = \dfrac{3.5}{6.06}

\theta = \arctan{left(\dfrac{3.5}{6.06}\right)}

\theta = 0.5236 \text{radians}

to convert radians to degrees:

\theta = 0.5236 \times \dfrac{180}{\pi} \approx 30^\circ

writing in polar coordinates:

r\angle\theta = 7\angle30^\circ\,\,\text{OR}\,\,7\angle0.5236\,\text{radians}

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