Question

The arch of a bridge can be modeled by d="TexFormula1" title="y=-\frac{1}{170}(x-225)(x+225)" alt="y=-\frac{1}{170}(x-225)(x+225)" align="absmiddle" class="latex-formula">, where $x$ and $y$ are measured in feet. The $x$-axis represents the ground. Find the width of the arch of the bridge at ground level.

Answer 1

Answer:

450 feet at ground level

Step-by-step explanation:

The width of the bridge at ground level will be where the function intercepts the x-axis also known as the roots or zeros of the function. They are found using the zero product property to set each factor equal to 0.

This means (x-225) = 0 and (x + 225) = 0. So x = -225, 225.

This means the width is the absolute value of |-225| + 225 since distance cannot be negative. This makes it 450 feet.

Answer 2

Answer is provided in the image attached.

Have a great day!

-TheBlueFox-