The total number of digits used when the first 2002 positive even integers are written is 4 digits
<h3>How to find the number of sequence?</h3>
Using arithmetic sequence,
nth term = a + (n - 1)d
where
- a = first term
- d = common difference
- n = number of terms
a = 2
d = 2
nth term = 2 + (2002 - 1)2
nth term = 2 + 4002
nth term = 4004
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Answer:
Yup! Great Job!
Step-by-step explanation:
Don't know try something else it will probably help
C. Is try correct answer
See example in the attached picture
Answer:
You need to do 5 times 3 for 15 a d then add 9 to get 24, so 47 is not less than or equal to 5 times 3 add 9
Step-by-step explanation:
