Question

1. Joy wants to find the distance, AB, across a creek. She starts at point B and walks along the edge of the river 105 ft and marks point C. Then she walks 85 ft further and marks point D. She turns 90° and walks until her final location and marks point E. Point E, point A, and point C are co-linear.

Answer 1

Answer:

The answer to your question is below

Step-by-step explanation:

a) Yes, Joy can conclude that ΔABC is similar to ΔEDC because

∠ACB ≅ ∠ECD    they are vertical angles and,

∠ABC ≅ ∠EDC    they are right angles

We conclude that ΔABC is similar to ΔEDC  because of the AA postulate.

b)       $\frac{AB}{BC} = \frac{DE}{CD}$

Solve for AB

        AB = (BC)(DE) / (CD)

Substitution

        AB = 105 (90) / 85

Simplification

        AB = 105(1.06)

Result

        AB = 111.2 ft