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3 years ago

What is 5.524 rounded to the nearest tenth

2 answers:

4 0

4 is less than 4 so the 2 stays the same and then the 5 stays the same
5.524 rounded to the nearest thenth is 5.5
Your answer is 5.5
Tip: 4 or less let it rest 5 or more let is sore

patriot [66]3 years ago

4 0

5.5
The 4 rounds the 2 down, resulting in 5.5

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Input in standard form the equation of the given line. The line with m = -1/2 and b = 1

Georgia [21]

Exact Form:

−1/2, b = 1

-12,b=1

Decimal Form:

−0.5,b=1

IF YOU LIKE MY ANSWER PLS GIVE ME BRAINLIEST!!

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4 years ago

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Answer the 3 screenshotted questions below. 30 points!

Triss [41]

Answer:

13. $36a^2b^4$ π

14. $16x^3y^4$ π

15. $-\frac{c^3}{4a^7b^3}$

Step-by-step explanation:

13.

A = π * $r^2$

r = $6ab^2$

A = π* $(6ab^2)^2$

A = π * $(6ab^2)(6ab^2)$

A = π * $36a^2b^4$

A = $36a^2b^4$ π

14.

V = π * $r^2$ * h

r = $2x$

h = $4xy^4$

V = π * $(2x)^2$ * $4xy^4$

V = π * $4x^2$ * $4xy^4$

V = π * $16x^3y^4$

V = $16x^3y^4$ π

15. $\frac{3a^{-4}b^2}{-12a^3b^5c^{-3}}$ = $-\frac{c^3}{4a^7b^3}$

$\frac{3a^{-4}b^2}{-12a^3b^5c^{-3}}$

$\frac{a^{-4}}{-4a^3b^5c^{-3}}$

$\frac{b^2}{-4^{3+4}b^5c^{-3}}$

$\frac{b^2}{-4^7b^5c^{-3}}$

$\frac{1}{-4a^7b^{5-2}c^{-3}}$

$\frac{1}{-4a^7b^3c^{-3}}$

$\frac{c^3}{-4a^7b^3}$

$-\frac{c^3}{4a^7b^3}$

Hope this helps!

3 0

3 years ago

Prompt Describe a simulation used to determine a game of darts. Plzzzzz help???

UkoKoshka [18]

Answer:

Anonymous simulation would be used to determine a game of darts.

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3 years ago

You are having a dinner catered. You pay a rental fee of $150 for the dining hall, and you pay the caterer $10 for each person w

Verdich [7]

Answer:

$13

Step-by-step explanation:

For 50 people it will cost you 150 + 50(10) or 500

150 +500 = 650 Divide that among 50 people and you get a cost of $13 a person.

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2 years ago

Jerald jumped from a bungee tower. If the equation that models his height, in feet, is h = –16t2 + 729, where t is the time in s

Snezhnost [94]

Answer. First option: t > 6.25

Solution:

Height (in feet): h=-16t^2+729

For which interval of time is h less than 104 feet above the ground?

h < 104

Replacing h for -16t^2+729

-16t^2+729 < 104

Solving for h: Subtracting 729 both sides of the inequality:

-16t^2+729-729 < 104-729

-16t^2 < -625

Multiplying the inequality by -1:

(-1)(-16t^2 < -625)

16t^2 > 625

Dividing both sides of the inequality by 16:

16t^2/16 > 625/16

t^2 > 39.0625

Replacing t^2 by [ Absolute value (t) ]^2:

[ Absolute value (t) ]^2 > 39.0625

Square root both sides of the inequality:

sqrt { [ Absolute value (t) ]^2 } > sqrt (39.0625)

Absolute value (t) > 6.25

t < -6.25 or t > 6.25, but t can not be negative, then the solution is:

t > 6.25

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4 years ago

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