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Fynjy0 [20]
3 years ago
6

Part A: Sam rented a boat at $225 for 2 days. If he rents the same boat for 5 days, he has to pay a total rent of $480.

Mathematics
1 answer:
miss Akunina [59]3 years ago
4 0

Answer:

Here's what I get.

Step-by-step explanation:

Part A. Equation in standard form

The question is asking you to find the equation of a straight line that passes through two points

Let x = the number of days

and y = the cost

Then the coordinates of the two points are (2,225) and (5,480).

(i) Calculate the slope of the line

\begin{array}{rcl}m & = & \dfrac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\& = & \dfrac{480 - 225}{5 - 2}\\\\& = & \dfrac{255}{3}\\\\& = & 85\\\end{array}

In other words, the daily rental is $85/day.

(ii) Calculate the y-intercept

\begin{array}{rcl}y & = & mx + b\\480 & = & 85 \times 5 + b\\480 & = & 425 + b\\b & = & 55\\\end{array}

(iii) Write the equation for the line

y = 85x + 55

That is, the cost is $55  plus $85/day

Part B. Equation in function notation

Replace y with ƒ(x)

ƒ(x) = 85x + 55

Part C. Graphing

Let's say you want to plot a graph of the rental cost for up to ten days.

(i) Calculate two points on the graph.

When x = 0, y = 85; when x = 10, y = 905.

(ii) Scale your axes

A good number of intervals is about ten.

Your x-axis should have tick marks at 1-day intervals.

Your largest y-value is 905. Ten intervals would make about $90/interval. However, you should round that up to $100/interval for easy interpolation.

Your y-axis will run from 0 to $1000 in $100 intervals.

Plot your two points and draw a straight line through them.

(iii) Axis labels

x represents the number of days, so the label on the x-axis could be "No. of days."

y represents the cost of renting the boat, so the label on the y-axis could be "Rental cost."

Your graph should resemble the one below.

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Given the midpoint and one endpoint of a line segment, find the other endpoint.
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Answer:

(-12 , 2)

Step-by-step explanation:

<u>GIVEN :-</u>

  • Co-ordinates of one endpoint = (-4 , -10)
  • Co-ordinates of the midpoint = (-8 , -4)

<u>TO FIND :-</u>

  • Co-ordinates of another endpoint.

<u>FACTS TO KNOW BEFORE SOLVING :-</u>

<em><u>Section Formula :-</u></em>

Let AB  be a line segment where co-ordinates of A = (x¹ , y¹) and co-ordinates of B = (x² , y²). Let P be the midpoint of AB . So , by using section formula , the co-ordinates of P =

(x , y) = (\frac{x^2 + x^1}{2} ,\frac{y^2 + y^1}{2} )

<u>PROCEDURE :-</u>

Let the co-ordinates of another endpoint be (x , y)

So ,

(-8 , -4) = (\frac{-4 + x}{2} , \frac{-10 + y}{2} )

First , lets solve for x.

=> \frac{x - 4}{2} = -8

=> x - 4 = -8 \times 2 = -16

=> x = -16 + 4 = -12

Now , lets solve for y.

=> \frac{y - 10}{2} = -4

=> y - 10 = -4 \times 2 = -8

=> y = -8 + 10 = 2

∴ The co-ordinates of another endpoint = (-12 , 2)

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If y=56+7+8x find x​
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Step-by-step explanation:

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My pigg y bank has only pennies and nicklels in it , and 2/7 of the coins are nickel If i remove 84 pennies then 1/3 of the reme
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Answer:

There are 105 pennies in the piggy bank.

There are 42 nickels in the piggy bank.

Step-by-step explanation:

there are:

p pennies in the piggy bank

n nickels in the piggy bank

Then we can define T, the total number of coins, as:

T = p + n

We know that 2/7 of the total number of coins are nickels.

This can be written as:

n = (2/7)*T = (2/7)*(n + p)

And if we remove 84 pennies, 1/3 of the remaining coins are pennies.

This can be written as:

p - 84 = (1/3)*(n + p - 84)

Then we have a system of two equations:

n = (2/7)*(n + p)

p - 84 = (1/3)*(n + p - 84)

Let's solve the system, to do it, we first need to isolate one of the variables in one of the equations.

We can isolate n in the first one, to get:

n = (2/7)*(n + p) = (2/7)*n + (2/7)*p

n - (2/7)*n = (2/7)*p

n*(5/7) = (2/7)*p

n = (7/5)*(2/7)*p = (2/5)*p

n = (2/5)*p

Now we can replace this in the other equation:

p - 84 = (1/3)*(n + p - 84)

p - 84 = (1/3)*( (2/5)*p + p - 84)

Let's solve this for p

p - 84 = (1/3)*( (7/5)*p - 84)

3*(p - 84) = (7/5)*p - 84

3p - 252 = (7/5)*p - 84

3*p - (7/5)*p = 252 - 84

(15/5)*p - (7/5)*p = 168

(8/5)*p = 168

p = (5/8)*168 = 105

There are 105 pennies in the piggy bank.

And we know that:

n = (2/5)*p = (2/5)*105 = 42

There are 42 nickels in the piggy bank.

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3 years ago
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