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3 years ago

If f(x) = x^5 - 1, g(x) = 5x, and h(x) = 2x, which expression is

Mathematics

1 answer:

Bad White [126]3 years ago

6 0

The answer is 5(2-9)-1)2

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What do a rectangle and a rhombus have in common? Select all that apply.

sleet_krkn [62]

The opposite sides are parallel.
Their angle measures add to 360°.

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3 years ago

2 + 3 + 8 + 1 + 9 + 10 - 11 +10 = ?

Illusion [34]

The answer is 32 ………………..

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2 years ago

Read 2 more answers

Find the slope of the line shown on the graph to the right

damaskus [11]

Answer:

Step-by-step explanation:

We need two points to find the slope

( -1,0) and ( 2,3)

We can use the slope formula

m = ( y2-y1)/(x2-x1)

= ( 3-0)/(2 - -1)

= (3-0) / ( 2+1)

= 3/3

= 1

The slope is 1

6 0

2 years ago

Solve for e. T=e29 e=±3T√T e=±3T e=±3T√ e=±9T√

Anon25 [30]

Answer:

option (3) is correct.

$e= \pm 3\sqrt{T}$

Step-by-step explanation:

Given $T=\frac{e^2}{9}$

We have to solve for e.

Consider the given statement,

$T=\frac{e^2}{9}$

Cross multiply, we get,

$\Rightarrow 9T={e^2}$

Taking square root both sides , we get,

$\Rightarrow \sqrt{9T}=e$

We know square root of 9 is 3.

$\Rightarrow \pm 3\sqrt{T}=e$

Thus, option (3) is correct.

$e= \pm 3\sqrt{T}$

4 0

2 years ago

Write a definite integral that represents the area of the region. (Do not evaluate the integral.)

joja [24]

Answer:

$\int_{-1}^{1}7(x^{3}-x)\:dx$

Step-by-step explanation:

1) The other curve is $y=0$ then the common points of both curves are x-intercepts, the roots of $y=7(x^{3}-x)$

$y=7(x^{3}-x)\Rightarrow 7(x^3-x)=0 \Rightarrow 7(x^{3}-x)=7x(x-1)(x-1)\Rightarrow \\S=\left ( 0,0 \right ),\left ( -1,0 \right ),\left ( 1,0 \right )$

2). Then those intersection points are the upper and the lower limits. Plugging in to this formula for they belong to the interval [-1,1]:

$\int_{a}^{b}|f(x)-g(x)dx$

$\int_{a}^{b}|f(x)-g(x)dx \Rightarrow \int_{-1}^{1}|7(x^{3}-x)-0|dx \Rightarrow \int_{-1}^{1}7(x^{3}-x)\:dx$

8 0

3 years ago