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2 years ago

Which of these lines passes through the point (1,-1) and has a slope of -3?

Mathematics

1 answer:

olga nikolaevna [1]2 years ago

7 0

Answer:

Step-by-step explanation:

We can write the equation using the point and the slope .

Formula we need to use is the point slope formula

Which is given by

Y-y1= m(X-x1)

Here given that (x1,y1)=(1,-1) and m = -3

x1= 1

y1 = -1

so equation is

Y-(-1) = -3 (x-1)

Distribute the slope

y+1 = -3x+3

y= -3x+3-1

y = -3x + 2

So the equation is

y =-3x +2

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2 years ago

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What's 46.82 rounded to the nearest ten?

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50 is 46.82 rounded to the nearest ten

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3 years ago

Kendal bought x boxes of cookies to bring to a party. Each box contains 12 cookies. She decides to keep two boxes for herself. S

Georgia [21]

Answer:

Step-by-step explanation:

Total number of boxes of cookies that Kendal bought to bring to the party is x.

Each box contains 12 cookies. This means that total number of cookies in x boxes would be

12 × x = 12x

She decides to keep two boxes for herself. This means that the total number of cookies that she kept for herself would be

12 × 2 = 24 cookies

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6 0

2 years ago

Please solve these questions for me. i am having a difficult time understanding.

s2008m [1.1K]

Answer:

1) AD=BC(corresponding parts of congruent triangles)

2)The value of x and y are 65 ° and 77.5° respectively

Step-by-step explanation:

Given : AD||BC

AC bisects BD

So, AE=EC and BE=ED

We need to prove AD = BC

In ΔAED and ΔBEC

AE=EC (Given)

$\angle AED = \angel BEC$ ( Vertically opposite angles)

BE=ED (Given)

So, ΔAED ≅ ΔBEC (By SAS)

So, AD=BC(corresponding parts of congruent triangles)

Hence Proved

Refer the attached figure

$\angle ABC = 90^{\circ}$

In ΔDBC

BC=DC (Given)

So, $\angle CDB=\angle DBC$ (Opposite angles of equal sides are equal)

So, $\angle CDB=\angle DBC=x$

So, $\angle CDB+\angle DBC+\angle BCD = 180^{\circ}$ (Angle sum property)

x+x+50=180

2x+50=180

2x=130

x=65

So, $\angle CDB=\angle DBC=x = 65^{\circ}$

Now,

$\angle ABC = 90^{\circ}\\\angle ABC=\angle ABD+\angle DBC=\angle ABD+x=90$

So, $\angle ABD=90-x=90-65=25^{\circ}$

In ΔABD

AB = BD (Given)

So, $\angle BAD=\angle BDA$ (Opposite angles of equal sides are equal)

So, $\angle BAD=\angle BDA=y$

So, $\angle BAD+\angle BDA+\angle ABD = 180^{\circ}$ (Angle Sum property)

y+y+25=180

2y=180-25

2y=155

y=77.5

So, The value of x and y are 65 ° and 77.5° respectively

8 0

3 years ago