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3 years ago

Which of these lines passes through the point (1,-1) and has a slope of -3?

Mathematics

1 answer:

olga nikolaevna [1]3 years ago

7 0

Answer:

Step-by-step explanation:

We can write the equation using the point and the slope .

Formula we need to use is the point slope formula

Which is given by

Y-y1= m(X-x1)

Here given that (x1,y1)=(1,-1) and m = -3

x1= 1

y1 = -1

so equation is

Y-(-1) = -3 (x-1)

Distribute the slope

y+1 = -3x+3

y= -3x+3-1

y = -3x + 2

So the equation is

y =-3x +2

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3 years ago

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3 years ago

Factor completely 18x2 − 21x −15. 3(2x 1)(3x − 5) 3(2x − 5)(3x 1) 3(2x − 1)(3x 5) 3(6x 1)(x − 5).

sergeinik [125]

The factor of the $18x^{2} -21x-15$ will be 3(3x-5)(2x+1).

<h3>What will be the factor of $18x^{2} -21x-15$ ?</h3>

Given quadratic equation is $18x^{2} -21x-15$

By taking 3 common from whole of the equation it becomes.

$3(6x^{2} -7x-5)$

now by factorization equation will be.

$3(6x^{2} -10x+3x-5)$

3[(2x(3x-5)+1(3x-5)]

Taking (3x-5) common from whole equation it will become

3(3x-5)(2x+1).

Hence the factor of the $18x^{2} -21x-15$ will be 3(3x-5)(2x+1).

To know more about factorization follow.

brainly.com/question/25829061

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2 years ago

Factor each.<br><br><br> Please help!

Naddika [18.5K]

Answer:

1) The factors of $x^2-3x+2=0$ are $\mathbf{(x-1)(x-2)=0}$

Option C is correct.

3) The factors of $x^2+2x-8=0$ are $\mathbf{(x-2)(x+4)=0}$

Option B is correct.

Step-by-step explanation:

1) Factor : $x^2-3x+2=0$

For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.

The middle term : -3x

We can break them as (-2x)( -x)

Solving:

$x^2-3x+2=0\\x^2-2x-x+2=0\\x(x-2)-1(x-2)=0\\(x-1)(x-2)=0$

So, factors of $x^2-3x+2=0$ are $\mathbf{(x-1)(x-2)=0}$

Option C is correct.

3) Factor: $x^2+2x-8=0$

For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.

The middle term : 2x

We can break them as (4x)( -2x)

Solving

$x^2+2x-8=0\\x^2+4x-2x-8=0\\x(x+4)-2(x+4)=0\\(x-2)(x+4)=0$

So, factors of $x^2+2x-8=0$ are $\mathbf{(x-2)(x+4)=0}$

Option B is correct.

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3 years ago

Josh bought 6 pounds of sugar for $4. How many pounds of sugar did he get per dollar?

Anit [1.1K]

1.5 pounds of sugar per dollar.

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3 years ago