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stealth61 [152]
3 years ago
7

Create a system of equations that are parallel to the y-axis.

Mathematics
1 answer:
pishuonlain [190]3 years ago
4 0

Answer:

the y-axis equation that are parallel is x-axis

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Suppose f (x) = x^2. Find the graph of f(x+2)
NISA [10]
\bf ~~~~~~~~~~~~\textit{function transformations}
\\\\\\
% templates
f(x)={{  A}}({{  B}}x+{{  C}})+{{  D}}
\\\\
~~~~y={{  A}}({{  B}}x+{{  C}})+{{  D}}
\\\\
f(x)={{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\\\
f(x)={{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\\\
f(x)={{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\\\\
--------------------

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\
~~~~~~\textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\
~~~~~~\textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
~~~~~~if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{  D}}\\
~~~~~~if\ {{  D}}\textit{ is negative, downwards}\\\\
~~~~~~if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

with that template in mind,

\bf f(x)=x^2\qquad \quad f(x+2)=(x+2)^2\implies f(x+2)=\stackrel{A}{1}(\stackrel{B}{1}x\stackrel{C}{+2})^2\stackrel{D}{+0}

C = 2         B = 1        C/B = 2/1 or +2,    horizontal left shift of 2 units

f(x) shifted left by 2 units is f(x+2).
8 0
3 years ago
Helppppppppppppppp lol
Sladkaya [172]
The given expression is: 
(x/2) + 5

Let's look at each terms separately:
x/2 means that you you're getting half the value of a number
+5 means that you are adding 5
Combining both, you can conclude that you are adding 5 to half a certain given number.

Comparing this with the choices, the correct choice would be:
C. five more than half a number.

5 0
3 years ago
Read 2 more answers
Mariela recolecto 625 mililitros de agua que gotea de su caño en 10 minutos, ella desea saber ¿cuanta agua gastara en una semana
mario62 [17]

Answer:

En una semana gastará 705,6 litros.

Step-by-step explanation:

Con la información proporcionada, puedes calcular cuánta agua gastará por día usando una regla de tres teniendo en cuenta que un día tiene 24 horas y estas equivalen a 1440 minutos. Además, puedes convertir los 700 ml a litros, considerando que 1 litro son 1000 mL, lo que significa que los 700 mL equivalen a 700/1000=0,7 Litros.

 10 min    →  0,7 L

1440 min →       x

x=(1440*0,7)/10

x=100,8 L

Ahora que conoces la cantidad de agua que gastará por día, puedes multiplicar esta cantidad por 7 que es el número de días en una semana:

100,8*7=705,6 L

De acuerdo a esto, la respuesta es que en una semana gastará 705,6 litros.

4 0
3 years ago
Help plz I need help
Whitepunk [10]
The first column is meters and the second column is centimeters. =)
8 0
3 years ago
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How fast does a ferrari go?
Usimov [2.4K]
Depends what Ferrari car it is.
6 0
3 years ago
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