3 years ago

Can someone please help me?

Mathematics

1 answer:

Goshia [24]3 years ago

7 0

If I read the graphs right, the correct answer should be B. 14. I hope I could help

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Solve for d.<br> d + 67 = 87<br> р<br> Submit

Vsevolod [243]

Answer:

$d=20$

Step-by-step explanation:

$d+67=87$

Subtract 67 from both sides

$d=20$

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7 0

3 years ago

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$350 at 3 1/2% for 3 years<br> 2

777dan777 [17]

Answer:

The answer is

Step-by-step explanation:

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2 years ago

Помогите, пожалуйста

Cerrena [4.2K]

6 - 2х² = 6 - 2(-8)² = 6 - 2(64) = 6 - 128 = -122

$\displaystyle\tt a^{11}\cdot a^{14}=a^{11+14}=a^{25}\\\\a^{18}:a^{14}=a^{18-14}=a^4\\\\(a^5)^4=a^{5\cdot4}=a^{20}\\\\(5x)^4=5^4\cdot x^4=625x^4\\\\\bigg(\frac{a}{3}\bigg)^6=\frac{a^6}{3^6}=\frac{a^6}{729}$

$\displaystyle\tt \frac{14^{16}\cdot14^{6}}{14^{21}}=14^{16+6-21}=14^1=14\\\\\\ \frac{7^{8}\cdot7^{5}}{7^{11}}=7^{8+5-11}=7^2=49\\\\\\ (12^2-11^2)^2+(6^5+2^9)^0=(144-121)^2+1=23^2+1=529+1=530$

$\displaystyle\tt 3^{8x}=81\\\\3^{8x}=3^4\\\\8x=4\\\\x=\frac{4}{8}=\frac{1}{2}=0.5$

$\displaystyle\tt \frac{64^{6}}{4^{4}\cdot4^{16}}=\frac{(4^3)^{6}}{4^{4+16}}=\frac{4^{3\cdot6}}{4^{20}}=\frac{4^{18}}{4^{20}}=\frac{1}{4^{2}}=\frac{1}{16}$