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Sphinxa [80]
4 years ago
12

Write a quadratic function in standard form with zeros 9 and -3 PLZZZZZ HELPP MEEE

Mathematics
1 answer:
Studentka2010 [4]4 years ago
7 0

Answer:

f(x)=x^2-6x-27

Step-by-step explanation:

x=9 and x-3

set the equal to zero: x-9=0 and x+3=0

x-9 and x+3 are now the factors of your equation:

you equation so far is: (x-9)(x+3)=0

next factor these together to get: f(x)=x^2+3x-9x-27

finally simplify the equation leaving you with f(x)=x^2-6x-27

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3 years ago
Point J is located at (-6, -2) on the coordinate plane. Point J is reflected over the
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J (-6 , -2), J': (-6 , 2), J'': (6 , 2)

Step-by-step explanation:

J (-6 , -2)

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Write the expression(4x-2)·6(2x+7) in the standard form of a quadratic expression, <br> ax²+bx+c
marysya [2.9K]
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x = <u>-144 +/- √(20,736 - 16,128)</u>
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6 0
3 years ago
Read 2 more answers
What is negative -6 in simplest form
IRISSAK [1]
-(-6) in simplest form is +6 because a - times a - is a +
7 0
3 years ago
Helppp!!!! please!!!
Kamila [148]

Answer:

<h2>           a.   1188 in.² </h2>

Step-by-step explanation:

Area of parallelogram is:  A = B•H     {H⊥B}

B = 36 in.

H = 33 in.

A = 36 in. • 33 in. = 1188 in.²

7 0
3 years ago
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