Can someone help me I appreciate it

A Department of Transportation report about air travel found that nationwide, 76% of all flights are on time. Base the following

ser-zykov [4K]

Answer:

30 flights are expected to be late.

Step-by-step explanation:

Consider the provided information.

A Department of Transportation report about air travel found that nationwide, 76% of all flights are on time.

That means 100-76% = 24% of all flights are not on time.

125 randomly selected flights.

We need to find flights would you expect to be late.

Flight expect to be late E(x) = nq

Here n is 125 and the probability of late is 24 or q = 0.24

Thus substitute the respective values in the above formula.

Flight expect to be late E(x) = 125 × 0.24 = 30

Hence, the 30 flights are expected to be late.

5 0

3 years ago

I need help what is 3/2 to the third power?

Drupady [299]

It’s the 9 because it’s 3 times 3

6 0

3 years ago

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Snowcat [4.5K]

Hi!

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Area of a triangle = $(base * height)/2$

Area of a square = $(side)^2$

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QUESTION 1: Determine the area of the triangular face.

$\frac{bh}{2}$

$32(20)/2$

$640/2$

$320$

The triangular face is 320 square feet.

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QUESTION 2: Determine the surface area of the entire figure.

$a^2$

$32^2$

$1024$

Now, add the 4 triangular faces to the area of the square face.

$1024+320(4)$

$1024+1280$

$2304$

The total surface area is 1204 square feet.

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For more information, see:

brainly.com/question/4637102

brainly.com/question/22971514

5 0

3 years ago

Please help me on this math

stellarik [79]

Friendly phone= 0.06×400=24; 0.25×400= 100; 100+24+3.95=127.95; 127.95×4= $511.8
Chatter= 0.098 × 400= 39.2; 0.192 × 400= 76.8; 76.8+39.2+4.95= 120.95; 120.95 × 4= $483.8
Phone A Lot= 0.089 × 400= 35.6; 0.24 × 400= 96; 35.6 + 96= 131.6;
131.6 × 4= $526.4

Chatter < Friendly phone < Phone A Lot
$483.8 < $511.8 < $526.4
The cheapest one would be Chatter= $483.8

Hope this helps :)

5 0

3 years ago

Scores of an IQ test have a bell-shaped distribution with a mean of 100 and a standard deviation of 17. Use the empirical rule

-BARSIC- [3]

Answer:

(a) 95% of people have an IQ score between 66 and 134.

(b) 32% of people have an IQ score of less than 83 or greater than 117.

(c) 16% of people have an IQ score greater than 117.

Step-by-step explanation:

We are given that scores of an IQ test have a bell-shaped distribution with a mean of 100 and a standard deviation of 17.

Let X = scores of an IQ test

SO, X ~ Normal( $\mu=100, \sigma^{2} = 17^{2}$ )

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

Now, the empirical rule states that;

68% of the data values lie within 1 standard deviation from the mean.

95% of the data values lie within 2 standard deviations from the mean.

99.7% of the data values lie within 3 standard deviations from the mean.

(a) The percentage of people having an IQ score between 66 and 134 is given by;

z score for 66 = $\frac{X-\mu}{\sigma}$ = $\frac{66-100}{17}$ = -2

z score for 134 = $\frac{X-\mu}{\sigma}$ = $\frac{134-100}{17}$ = 2

This means that the percentage of people having an IQ score between 66 and 134 is 95%.

(b) Firstly, we have to find the percentage of people having an IQ score between 83 and 117;

z score for 83 = $\frac{X-\mu}{\sigma}$ = $\frac{83-100}{17}$ = -1

z score for 117 = $\frac{X-\mu}{\sigma}$ = $\frac{117-100}{17}$ = 1

This means that the percentage of people having an IQ score between 83 and 117 is 68%.

This means that the percentage of people having an IQ score of less than 83 or greater than 117 = 100% - 68% = 32%.

(c) In the above part, we find that there are 32% of the values that have an IQ score of less than 83 or greater than 117.

This means that half of this will be less than 83 and half of this will be greater than 117.

So, the percentage of people having an IQ score greater than 117 = $\frac{32\%}{2}$ = 16%.

8 0

3 years ago