Answer:
93.32% probability that a randomly selected score will be greater than 63.7.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a randomly selected score will be greater than 63.7.
This is 1 subtracted by the pvalue of Z when X = 63.7. So



has a pvalue of 0.0668
1 - 0.0668 = 0.9332
93.32% probability that a randomly selected score will be greater than 63.7.
Answer:
2
Step-by-step explanation:
Total costs = 4 + (3 * 2) + 5 + 15
Total costs = 4 + 6 + 5 + 15
Total costs = $ 30
Substituting values we have:
Total change = 32 - 30
Total change = 2 $
Same number of rows to chairs in a row would form a square.
Use the total number of students as the area
Find the number or rows by taking the square root of student:
The square root of 7033 is 83.86
Round up to 84
Total seats would be rows x seats per row:
84 x 84 = 7,056 total seats
7056 seats - 7033 students = 23 empty seats