Answer:
same side interior angles
Step-by-step explanation:
<4 and <6 are same side interior angles
Same side interior angles are on the same side of the transversal and inbetween the two lines
Answer: 225 N + 165 N = 3.90×10.
Answer:
a = 3,137
Step-by-step explanation:
We have to use the sin rule to solve. THis gives ratios of side and opposite side's angle's sin.
Sin rule is:
![\frac{a}{SinA}=\frac{b}{SinB}=\frac{c}{SinC}](https://tex.z-dn.net/?f=%5Cfrac%7Ba%7D%7BSinA%7D%3D%5Cfrac%7Bb%7D%7BSinB%7D%3D%5Cfrac%7Bc%7D%7BSinC%7D)
First, we know there are 180 degrees in 3 angles of a triangle, so lets find ∠A:
∠A + ∠B + ∠C = 180
∠A + 11 + 75 = 180
∠A + 86 = 180
∠A = 180 - 86
∠A = 94
Now since we know the angle B and side b pair, we can relate with a and write the sin rule as:
![\frac{a}{SinA}=\frac{b}{SinB}\\\frac{a}{Sin94}=\frac{600}{Sin11}](https://tex.z-dn.net/?f=%5Cfrac%7Ba%7D%7BSinA%7D%3D%5Cfrac%7Bb%7D%7BSinB%7D%5C%5C%5Cfrac%7Ba%7D%7BSin94%7D%3D%5Cfrac%7B600%7D%7BSin11%7D)
Now we cross multiply and solve for side a:
![\frac{a}{Sin94}=\frac{600}{Sin11}\\aSin11=600Sin94\\a=\frac{600Sin94}{Sin11}\\a=3137](https://tex.z-dn.net/?f=%5Cfrac%7Ba%7D%7BSin94%7D%3D%5Cfrac%7B600%7D%7BSin11%7D%5C%5CaSin11%3D600Sin94%5C%5Ca%3D%5Cfrac%7B600Sin94%7D%7BSin11%7D%5C%5Ca%3D3137)
So last answer choice is right, a = 3137
Answer:
-36x^3 - 69x^2 - 34x - 5
Step-by-step explanation:
(4x + 5) (3x + 1) -3 (x + 1)
(4x + 5) (3x + 1) ( -3x - 1)
12x^2 + 4x + 15x +5
Combine like terms
12x^2 + 19x + 5 (-3x - 1)
-36x^3 -57x^2 - 15x^2 -5
Combine like terms
-36x^3 - 69x^2 - 34x - 5
Answer:
The height of the another cylinder 'h' = 7
Step-by-step explanation:
<u>Explanation</u>:-
<u>Step 1:-</u>
Surface area of the cylinder = 2пrh + 2пr^2
Given radius of first cylinder is 20cm
given height of the first cylinder is 2 cm
The surface area of first cylinder is = 2пrh + 2пr^2
= 2п(20)(2)+2п(2)^2
= 4п(20+2)
The surface area of first cylinder is 88п
<u>Step 2</u>:
given data The surface area of first cylinder is 88п is same as second cylinder also
<u>Find the height of the second cylinder</u>
Given Radius of the second cylinder r = 4
Surface area of the cylinder = 2пrh + 2пr^2 = 88п
2п(4)h+2п(4)^2 =88п
on simplification we get
2п (4h+16) = 88п
after cancellation '2п' value and on simplification, we get
4h+16 = 44
4h = 44-16
4h = 28
h=7
Therefore the height of the another cylinder is 'h' =7