Answer:
80 Students are in the band class
Step-by-step explanation:
I did this mentally so sorry if it is bad
16 = 20%
+
16 = 20%
= 40% 32 students
40% +40% = 80%
32+ 32 = 64
80+20%
64+16
80 Students are in the band class
Answer:
x = -19/2 y = -33/2
Step-by-step explanation:
x - (3x + 12) = 7
x - 3x - 12 = 7
-2x - 12 = 7
-2x = 19
x = -19/2
x - y = 7
-19/2 - y = 7
-y = 33/2
y = -33/2
There is no solution ,<span>a+c=-10;b-c=15;a-2b+c=-5 </span>No solution System of Linear Equations entered : [1] 2a+c=-10
[2] b-c=15
[3] a-2b+c=-5
Equations Simplified or Rearranged :<span><span> [1] 2a + c = -10
</span><span> [2] - c + b = 15
</span><span> [3] a + c - 2b = -5
</span></span>Solve by Substitution :
// Solve equation [3] for the variable c
<span> [3] c = -a + 2b - 5
</span>
// Plug this in for variable c in equation [1]
<span><span> [1] 2a + (-a +2?-5) = -10
</span><span> [1] a = -5
</span></span>
// Plug this in for variable c in equation [2]
<span><span> [2] - (-? +2b-5) + b = 15
</span><span> [2] - b = 10
</span></span>
// Solve equation [2] for the variable ?
<span> [2] ? = b + 10
</span>
// Plug this in for variable ? in equation [1]
<span><span> [1] (? +10) = -5
</span><span> [1] 0 = -15 => NO solution
</span></span><span>No solution</span>
Answer:
C. Yes, 3.5.
Step-by-step explanation:
If there is a relationship of direct proportionality for every ordered pair of the table, then the constant of proportionality must the same for every ordered pair. The constant of proportionality (
) is described by the following expression:
(1)
Where:
- Input.
- Output.
If we know that 
, 
and 
, then the constants of proportionalities of each ordered pair are, respectively:
Since 
, the constant of proportionality is 3.5.
Answer:
A. Men had less distress from nausea on average than women but we can not determine if this is a significant difference.
Step-by-step explanation:
Working based on the information given, the mean values of each group with with men having an average score of 1.02 and women have an average of 1.79 this reveals that distressing nausea on average is higher in women than in men . However, to test if there is a significant difference would be challenging as the information given isn't enough to make proceed with the test as the standard deviations of the two groups aren't given and no accompanying sample data is given.
