Answer:
In Labrador dogs, black coat is dominant to chocolate, normal vision is dominant to progressive retinal atrophy (PRA), and normal hip joint is dominant to hip dysplasia. All these genes assort independently. Two dogs that are heterozygous for alleles of all three genes are crossed. Using rules of probability (not a Punnett square), what is the chance that the first pup born to these dogs will be chocolate, have normal vision, and have normal hip joints?
BbVvHh x BbVvHh= BBVVHH, BbVvHh, BbVvHh, bbvvhh
Bb= black coat dominant
Vv= Normal vision dominant
Hh= Normal hip join dominant
probability of having a first born of these dogs will be chocolate, have normal vision and have normal hip joint is 0
Explanation:
As the punette square gives 3:1 phenotype having three black coat, normal vision and normal hip joint and one chocolate, progressive retina altropy and hip dysplasia
Answer:
most likely disruptive selection
Explanation:
pretty sure they will reproduce to make slightly bigger offspring that can hide in rocks and stay warm
Answer:The physiological response is to maintain a neutral PH.
Explanation:
Answer:
The correct answer is Single Circular DNA Molecule.
Explanation:
A bacterial genome, which is the DNA that is found in bacteria collectively, is a double stranded circular DNA. So it has no start and end like double stranded helix DNA. The option D, which is "Single Circular DNA Molecule" is correct.
I hope this answer helps.
A ribosome coordinates translation.
