Answer:
Part 1: N(x) = 50,000 - 300(x-19)
Part 2: R(x) =-300x² + 55700x
Step-by-step explanation:
Given,
The original price of each ticket = $ 19,
The original attendance = 50,000
Part 1 :
∵ For the each $1 increase in the ticket price, attendance decreases by 300.
Let x represents the price of each ticket after increment,
Thus, if price increment = (x-19) dollars,
New attendance, N(x) = 50,000 - 300(x-19)
Part 2 :
Since, revenue = price of each ticket × attendance
Thus, the revenue from the football game,
R(x) = x(50,000 - 300(x-19))
R(x) = 50000x - 300x²+ 5700x
⇒ R(x) =-300x² + 55700x
