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QveST [7]
4 years ago
12

Leonardo ate a 3/5 of cheeseburger and an entire salad for dinner. The salad contained 70 calories and the entire meal contained

1650 calories. Which equation can determine the value, c, the number of calories in the cheeseburger?
Mathematics
2 answers:
Kipish [7]4 years ago
8 0

Answer:

C = [5(1650 - 70)]/3

Step-by-step explanation:

We write the equation: 1650 = 70 + 3C/5

Subtract 70 from both sides: 1650 - 70 = 3C/5

Multiply 5 on both sides: 5(1650 - 70) = 3C

Divide 3 on both sides : C = [5(1650 - 70)]/3

Doss [256]4 years ago
3 0

Answer:

3/5 c + 70 = 1650.

Step-by-step explanation:

If c is the number of calories in the cheeseburger, we can see that the entire number of calories for the meal is 3/5 c + 70 = 1650.

If we want to isolate c, we can subtract both sides by 70.

3/5 c = 1580

You might be interested in
What is (0 9 -3 6) (4 -3 5 0)
liraira [26]

Answer:

9342

Step-by-step explanation:

(09-36)(4-350)

Clear brackets, we have

36-3150-144+12600

=36-3294+12600

=-3258++2600

=9342

4 0
3 years ago
Help !
aivan3 [116]

Answer:

a. p(orange) = 5/14

b. p(green) = 3/14

c. p(red) = 1/7  

d. p(brown) = 2/7  

e. p(brown or red) = 3/7

Step-by-step explanation:

1. You have a 14 pencils. Two pencils are red, 5 pencils are orange, 3 pencils are green and 4 pencils are brown.

p(color) = (number of pencils of that color)/(total number of pencils)

p(color) = (number of pencils of that color)/14

a. If a pencil is picked at random, what is the probability that the pencil

will be orange?

p(orange) = 5/14

b. If a pencil is picked at random, what is the probability that the pencil

will be green?

p(green) = 3/14

c. If a pencil is picked at random, what is the probability that the pencil will be red?

p(red) = 2/14 = 1/7

d. If a pencil is picked at random, what is the probability that the pencil

will be brown?

p(brown) = 4/14 = 2/7

e. If a pencil is picked at random, what is the probability that the pencil

will be brown or red?

brown: 4

red: 2

brown or red: 4 + 2

p(brown or red) = 6/14 = 3/7

3 0
3 years ago
Figure ABCD is plotted on a coordinate plane. The figure transforms to create figure A'B'CD'. Which transformation took place?
bulgar [2K]

Answer: A(3,4) A'(-3,4)

B(5,4) B'(-5,4)

C(4,2) C'(-4,2)

D(2,2) D'(-2,2)

Step-by-step explanation:

5 0
4 years ago
PLZ Help!!!<br> Look at the pic.
stealth61 [152]
435 being the constant means that is what they started with

Hope this helps :)
8 0
3 years ago
Read 2 more answers
Can someone explain this to me please
IrinaVladis [17]

Answer:

c. 36·x

Step-by-step explanation:

Part A

The details of the circle are;

The area of the circle, A = 12·π cm²

The diameter of the circle, d = \overline {AB}

Given that \overline {AB} is the diameter of the circle, we have;

The length of the arc AB = Half the the length of the circumference of the circle

Therefore, we have;

A = 12·π = π·d²/4 = π·\overline {AB}²/4

Therefore;

12 = \overline {AB}²/4

4 × 12 = \overline {AB}²

\overline {AB}² = 48

\overline {AB} = √48 = 4·√3

\overline {AB} = 4·√3

The circumference of the circle, C = π·d = π·\overline {AB}

Arc AB = Half the the length of the circumference of the circle = C/2

Arc AB = C/2 = π·\overline {AB}/2

\overline {AB} = 4·√3

∴ C/2 = π·4·√3/2 = 2·√3·π

The length of arc AB = 2·√3·π cm

Part B

The given parameters are;

The length of \overline {OF} = The length of \overline {FB}

Angle D = angle B

The radius of the circle = 6·x

The measure of arc EF = 60°

The required information = The perimeter of triangle DOB

We have;

Given that the base angles of the triangles DOB are equal, we have that ΔDOB is an isosceles triangle, therefore;

The length of \overline {OD} = The length of \overline {OB}

The length of \overline {OB} = \overline {OF} + \overline {FB} = \overline {OF} + \overline {OF} = 2 × \overline {OF}

∴ The length of \overline {OD} = 2 × \overline {OF} = The length of \overline {OB}

Given that arc EF = 60°, and the point 'O' is the center of the circle, we have;

∠EOF = The measure of arc EF = 60° = ∠DOB

Therefore, in ΔDOB, we have;

∠D + ∠B = 180° - ∠DOB = 180° - 60° = 120°

∵ ∠D = ∠B, we have;

∠D + ∠B = ∠D + ∠D = 2 × ∠D = 120°

∠D = ∠B = 120°/2 = 60°

All three interior angles of ΔDOB = 60°

∴ ΔDOB is an equilateral triangle and all sides of ΔDOB are equal

Therefore;

The length of \overline {OD} = The length of \overline {OB} = The length of \overline {DB}  = 2 × \overline {OF}

The perimeter of ΔDOB = The length of \overline {OD} + The length of \overline {OB} + The length of \overline {DB} = 2 × \overline {OF} + 2 × \overline {OF} + 2 × \overline {OF} = 6 × \overline {OF}

∴ The perimeter of ΔDOB = 6 × \overline {OF}

The radius of the circle = \overline {OF} = 6·x

∴ The perimeter of ΔDOB = 6 × 6·x = 36·x

3 0
3 years ago
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