25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
Same side interior angles are not always congruent
Answer:
8 m3
Step-by-step explanation:
Since Box A has a volume of 64 cubic meters, that means each side length is 4 m3. It says to make Box B, they divided these lengths by 2. With that info, you get 8 as your volume
So what you would do is divide 988 by 26 and divide 731 by 17 and those two numbers you would add which gives you the amount of people that attended the performance
4,165 because you have to subtract the 4200 and 35 because when you read the word problem it says difference which means subtract
