lst=([])
def avgGPA(lst1):
total = 0
count = 0
for x in lst:
if type(x) == int:
total += x
count += 1
return total/count
def GPAcalc(grade, weighted):
grade = grade.lower()
dictionary = {"a": 4, "b": 3, "c": 2, "d": 1, "f": 0}
if weighted == 1 and grade in dictionary:
lst.append(dictionary[grade]+1)
return "Your GPA score is: " + str(dictionary[grade] + 1)
elif weighted == 0 and grade in dictionary:
lst.append(dictionary[grade])
return "Your GPA score is: " + str(dictionary[grade])
else:
lst.append("Invalid")
return "Invalid"
classes = int(input("How many Classes are you taking? "))
i = 0
while i < classes:
print(GPAcalc(input("Enter your Letter Grade: "), int(input("Is it weighted? (1 = yes) "))))
i += 1
print("Your weighted GPA is a "+str(avgGPA(lst)))
If you need me to change any code, I'll do my best. I hope this helps!
Answer :
The output is attached below
Explanation:
The following formula needs to be entered into cell N5:
=IF($M5>=4,"Lead","Associate")
Answer:
Web design is very unique, you can express your feelings through creating a page.
