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Keith_Richards [23]
2 years ago
12

What standards organization maintains the ethernet standard?.

Computers and Technology
1 answer:
Fofino [41]2 years ago
5 0

Answer:

Ethernet standards are written and maintained by the IEEE, the Institute of Electrical and Electronic Engineers which has its corporate office in New York City and its operations center in Piscataway, New Jersey.

Explanation:

You might be interested in
[1] Please find all the candidate keys and the primary key (or composite primary key) Candidate Key: _______________________ Pri
AVprozaik [17]

Answer:

Check the explanation

Explanation:

1. The atomic attributes can't be a primary key because the values in the respective attributes should be unique.

So, the size of the primary key should be more than one.

In order to find the candidate key, let the functional dependencies be obtained.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

Closure of attribute { Emp_ID, Date_Completed } is { Emp_ID, Date_Completed , Name, DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Name , Date_Completed } is { Name, Date_Completed , Emp_ID , DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { DeptID, Date_Completed } is { DeptID, Date_Completed , Emp_ID,, Name, , Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Marketing, Date_Completed } is { Marketing, Date_Completed , Emp_ID,, Name, DeptID , Salary, Course_Name, Course_ID}.

So, the candidate keys are :

{ Emp_ID, Date_Completed }

{ Name , Date_Completed }

{ DeptID, Date_Completed }

{ Marketing, Date_Completed }

Only one candidate key can be a primary key.

So, the primary key chosen be { Emp_ID, Date_Completed }..

2.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

3.

For a relation to be in 2NF, there should be no partial dependencies in the set of functional dependencies.

The first F.D. is

Emp_ID -> Name, DeptID, Marketing, Salary

Here, Emp_ID -> Salary ( decomposition rule ). So, a prime key determining a non-prime key is a partial dependency.

So, a separate table should be made for Emp_ID -> Salary.

The tables are R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

and R2( Emp_ID , Salary)

The following dependencies violate partial dependency as a prime attribute -> prime attribute :

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

The following dependencies violate partial dependency as a non-prime attribute -> non-prime attribute :

Course_ID -> Course Name

Course_Name ->  Course_ID

So, no separate tables should be made.

The functional dependency Date_Completed -> Course_Name has a partial dependency as a prime attribute determines a non-prime attribute.

So, a separate table is made.

The final relational schemas that follows 2NF are :

R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

R2( Emp_ID , Salary)

R3 (Date_Completed, Course_Name, Course_ID)

For a relation to be in 3NF, the functional dependencies should not have any transitive dependencies.

The functional dependencies in R1(Emp_ID, Name, DeptID, Marketing, Date_Completed) is :

Emp_ID -> Name, DeptID, Marketing

This violates the transitive property. So, no table is created.

The functional dependencies in R2 (  Emp_ID , Salary) is :

Emp_ID -> Salary

The functional dependencies in R3 (Date_Completed, Course_Name, Course_ID) are :

Date_Completed -> Course_Name

Course_Name   ->  Course_ID

Here there is a transitive dependency as a non- prime attribute ( Course_Name ) is determining a non-attribute ( Course_ID ).

So, a separate table is made with the concerned attributes.

The relational schemas which support 3NF re :

R1(Emp_ID, Name, DeptID, Course_ID, Marketing, Date_Completed) with candidate key as Emp_ID.

R2 (  Emp_ID , Salary) with candidate key Emp_ID.

R3 (Date_Completed, Course_Name ) with candidate key Date_Completed.

R4 ( Course_Name, Course_ID ).  with candidate keys Course_Name and Course_ID.

6 0
3 years ago
Which of the following are peripheral devices?
Fittoniya [83]

Explanation:

I think it's speakers,

7 0
3 years ago
Read 2 more answers
Need the answer ASAP !!!!
Nuetrik [128]

Answer:

periodic checks

Explanation:

6 0
2 years ago
In this lab, you complete a prewritten C++ program that calculates an employee’s productivity bonus and prints the employee’s na
Bas_tet [7]

Answer:

The answer to this question is given below in the explanation section

Explanation:

    The formula for productivity socre is      

 productivity score = ((transaction dollar value/no of transaction)/no of shift)

Productivity Score Bonus  is:  

<=30 $50

31–69 $75

70–199 $100

>= 200 $200

........................................................................................................................................

the code is given below

........................................................................................................................................

#include <iostream>

using namespace std;

int main()

{

   string firstName;

   string lastName;

   int noOfShift;

   int noOfTransaction;

   int transactionDollarValue;

   int productivityScore;

   int bonus;

   

   cout<<"Employee’s first name: ";

   cin>>firstName;

   cout<<"Employee's last name: ";

   cin>>lastName;

   cout<<"Number of shifts:";

   cin>>noOfShift;

   cout<<" Number of transactions: ";

   cin>>noOfTransaction;

   cout<<"Transaction dollar value:";

   cin>>transactionDollarValue;

   productivityScore = (transactionDollarValue/noOfTransaction)/noOfShift;

   

   if (productivityScore <= 30)

   {

       bonus =50;

       cout<<"Employee’s first name: "<<firstName<<" "<<lastName;

       cout<<endl;

       cout<<"Employee Bonuse: $"<<bonus;

       cout<<endl;

   }

   

   else if (productivityScore >= 79 && productivityScore <=199)

   

   {

       bonus =100;

       cout<<"Employee’s first name: "<<firstName<<" "<<lastName;

       cout<<"Employee Bonuse: $"<<bonus;

   }

   

   else if (productivityScore >= 200)

   

   {

       bonus =200;

       cout<<"Employee’s first name: "<<firstName<<" "<<lastName;

       cout<<"Employee Bonuse: $"<<bonus;

   }

   

   return 0;

}

               

       

6 0
3 years ago
Specific Instructions
Goryan [66]

In the most common use of the term, a class can be seen as a blueprint used to create objects. In other words, object(s) are created from a class in Java.

<h3>Creating a Class</h3><h3>Code:</h3>

import java.util.*;

class Card{

 private String suit;

 private int value;

 public Card(String s,int v){

   suit = s;

   value = v;

 }

 public String getSuit(){

   return suit;

 }

 public int getValue(){

   return value;

 }

 public void display(){

   System.out.println(value+"("+suit+")");

 }

}

class Deck{

 private ArrayList<Card> deck;

 private ArrayList<Card> drawn;

 public Deck(){

   deck = new ArrayList<Card>();

   drawn = new ArrayList<Card>();

   String[] arr = {"Club","Spade","Heart","Diamond"};

   for(String s : arr){

     for(int i=1;i<=13;i++){

       deck.add(new Card(s,i));

     }

   }

 }

 public void draw(){

   drawn.add(deck.get(0));

   deck.remove(0);

 }

 public void draw(int N){

   if(N > deck.size()){

     N = deck.size();

   }

   for(int i=0;i<N;i++){

     draw();

   }

 }

 public void showDrawn(){

   for(Card c : drawn){

     c.display();

   }

 }

 public void shuffle(){

   Collections.shuffle(deck);

 }

 public void restore(){

   restore(drawn.size());

 }

 public void restore(int N){

   if(N > drawn.size()){

     N = drawn.size();

   }

   for(int i=0;i<N;i++){

     deck.add(drawn.get(0));

     drawn.remove(0);

   }

 }

 public void showDeck(){

   for(Card c : deck){

     c.display();

   }

 }

}

class Test{

 public static void main(String[] args){

   Deck d = new Deck();

   System.out.println("Original deck\n");

   d.showDeck();

   d.draw(8);

   System.out.println("\nDeck after drawing 8 cards\n");

   d.showDeck();

   d.shuffle();

   System.out.println("\nDeck after shuffling\n");

   d.showDeck();

   d.restore();

   System.out.println("\nDeck after restoring cards\n");

   d.showDeck();

 }

}

<h3>Test Output:</h3>

C:\Users\hp\Desktop>java Test

Original deck

1(Club)

2(Club)

3(Club)

4(Club)

5(Club)

6(Club)

7(Club)

8(Club)

9(Club)

10(Club)

11(Club)

12(Club)

13(Club)

1(Spade)

2(Spade)

3(Spade)

4(Spade)

5(Spade)

6(Spade)

7(Spade)

8(Spade)

9(Spade)

10(Spade)

11(Spade)

12(Spade)

13(Spade)

1(Heart)

2(Heart)

3(Heart)

4(Heart)

5(Heart)

6(Heart)

7(Heart)

8(Heart)

9(Heart)

10(Heart)

11(Heart)

12(Heart)

13(Heart)

1(Diamond)

2(Diamond)

3(Diamond)

4(Diamond)

5(Diamond)

6(Diamond)

7(Diamond)

8(Diamond)

9(Diamond)

10(Diamond)

11(Diamond)

12(Diamond)

13(Diamond)

<h3>Draw action:</h3>

9(Club)

10(Club)

11(Club)

12(Club)

13(Club)

1(Spade)

2(Spade)

3(Spade)

4(Spade)

5(Spade)

6(Spade)

7(Spade)

8(Spade)

9(Spade)

10(Spade)

11(Spade)

12(Spade)

13(Spade)

1(Heart)

2(Heart)

3(Heart)

4(Heart)

5(Heart)

6(Heart)

7(Heart)

8(Heart)

9(Heart)

10(Heart)

11(Heart)

12(Heart)

13(Heart)

1(Diamond)

2(Diamond)

3(Diamond)

4(Diamond)

5(Diamond)

6(Diamond)

7(Diamond)

8(Diamond)

9(Diamond)

10(Diamond)

11(Diamond)

12(Diamond)

13(Diamond)

<h3 /><h3>Shuffling action:</h3>

12(Diamond)

8(Spade)

4(Spade)

6(Diamond)

10(Spade)

13(Club)

7(Heart)

13(Heart)

7(Diamond)

9(Heart)

11(Diamond)

5(Heart)

8(Diamond)

9(Diamond)

3(Spade)

13(Spade)

4(Heart)

2(Heart)

3(Heart)

5(Diamond)

11(Heart)

11(Club)

10(Club)

9(Club)

3(Diamond)

4(Diamond)

6(Spade)

9(Spade)

10(Heart)

11(Spade)

5(Spade)

12(Spade)

1(Spade)

6(Heart)

12(Heart)

13(Diamond)

1(Heart)

2(Diamond)

1(Diamond)

7(Spade)

12(Club)

10(Diamond)

2(Spade)

8(Heart)

  • Restore action

12(Diamond)

8(Spade)

4(Spade)

6(Diamond)

10(Spade)

13(Club)

7(Heart)

13(Heart)

7(Diamond)

9(Heart)

11(Diamond)

5(Heart)

8(Diamond)

9(Diamond)

3(Spade)

13(Spade)

4(Heart)

2(Heart)

3(Heart)

5(Diamond)

11(Heart)

11(Club)

10(Club)

9(Club)

3(Diamond)

4(Diamond)

6(Spade)

9(Spade)

10(Heart)

11(Spade)

5(Spade)

12(Spade)

1(Spade)

6(Heart)

12(Heart)

13(Diamond)

1(Heart)

2(Diamond)

1(Diamond)

7(Spade)

12(Club)

10(Diamond)

2(Spade)

8(Heart)

1(Club)

2(Club)

3(Club)

4(Club)

5(Club)

6(Club)

7(Club)

8(Club)

You can learn more about creating a class here brainly.com/question/10410845

6 0
2 years ago
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