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ValentinkaMS [17]
2 years ago
13

How do you solve this and what is the answer?

Mathematics
1 answer:
Sladkaya [172]2 years ago
7 0
We want to get rid of the square root sign somehow, so let's isolate that term.

2\sqrt{\frac{3x}{5}} + 3 = 11
2\sqrt{\frac{3x}{5}} = 11 - 3 = 8
\sqrt{\frac{3x}{5}} = 4

Now, in order to 'undo' a root sign, we need to do the opposite to it, by squaring the term, but in order for it to remain the same, we need to square 4 as well.

\frac{3x}{5} = 16

Now, we can isolate the variable:
3x = 5 \cdot 16 = 80
x = \frac{80}{3}, and since we can't simplify this further, our final answer becomes:

x = \frac{80}{3} or x = 26\frac{2}{3}
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By taking  = 3.141 and
Whitepunk [10]

The value of the expression 1/√2 + π where the given parameters are π = 3.141 and  √2 = 1.414 is 3.848

<h3>How to evaluate the expression?</h3>

The given parameters are

π = 3.141

√2 = 1.414

The expression to evaluate is given as:

1/√2 + π

Start by substituting π = 3.141 and √2 = 1.414 in the expressions 1/√2 + π

1/√2 + π = 1/1.414 + 3.141

Evaluate the quotient

1/√2 + π = 0.707 + 3.141

Evaluate the sum

1/√2 + π = 3.848

Hence, the value of the expression 1/√2 + π where the given parameters are π = 3.141 and  √2 = 1.414 is 3.848

Read more about expressions at:

brainly.com/question/723406

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<u>Complete question</u>

By taking π = 3.141 and √2 = 1.414, evaluate 1/√2 + π up to three places of decimals.

8 0
1 year ago
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