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gogolik [260]
3 years ago
5

A sequence is defined recursively by the following rules: f(1)=3f(n+1)=2⋅f(n)−1 Which of the following statements is true about

the sequence?
Select all that apply.
f(2)=5
f(6)=66
f(3)=10
f(4)=18
f(5)=33
Mathematics
1 answer:
Radda [10]3 years ago
4 0

Answer:

f(2)=5

f(5)=33

Step-by-step explanation:

The given formula, that recursively defines the sequence is

f(1) = 3 \\ f(n + 1) = 2f(n) - 1

When n=1, we obtain;

f(1+ 1) = 2f(1) - 1 \\ f(2) = 2 \times 3 - 1 \\ f(2) = 6 - 1 \\ f(2) = 5

When n=2, we get:

f(2+ 1) = 2f(2) - 1 \\ f(3) = 2 \times 5 - 1 \\ f(3) = 10 - 1 \\ f(3) = 9

When n=3,

f(3 + 1) = 2f(3) - 1 \\ f(4) = 2f(3) - 1 \\ f(4) = 2 \times 9 - 1 \\ f(4) = 18 - 1 \\ f(4) = 17

When n=4

f(4 + 1) = 2 f(4) - 1 \\ f(5) = 2 \times 17 - 1 \\ f(5) = 34 - 1 \\ f(5) = 33

When n=5,

f(6) = 65

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ABCD is a parallelogram. If ad = 2x + 10 and CD = 4x - 20, for what value of x will abcd be a rhombus
dimaraw [331]

Answer:

15

Step-by-step explanation:

All sides of a rhombus are equal, so

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11 months ago
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Picture attached with question
Mariana [72]

The function is stretched vertically by a factor of 3.

The function shifts 2 to the right.

The function is moved 5 units up.

Explanation:

The parent function of the graph is f(x)=\sqrt{x}

The transformation for the parent function is given by g(x)=3\sqrt{x-2} +5

Thus, the transformed function is in the form of y=a\sqrt{x-h} +k

where a is the vertical compression/stretch,

h moves graph to left or right and

k moves the graph up or down.

Thus, from the transformed function g(x)=3\sqrt{x-2} +5, we have,

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The attached graph below shows the transformation of the graph that the graph is stretched vertically by a factor of 3 and shifted 2 units to the right and moved 5 units up.

Hence, The function is stretched vertically by a factor of 3.

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