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kifflom [539]
3 years ago
10

What is the common factors of 91

Mathematics
2 answers:
Advocard [28]3 years ago
7 0
The only factors of 91 are 1 and 91.
erma4kov [3.2K]3 years ago
3 0
No.. 91 and 1 are not the only prime factors..

as 7 and 13 also multiply to make 91
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Alenkasestr [34]

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Step-by-step explanation:

this is a straight forward addition

2.5+3.03 =5.53

to be clear or to specify, use the decimal point to make the sum:

2.5 = 2 + 0.5       and 3.03 = 3 + 0.03

2+3= 5      and  0.5 + 0.03 = 0.53

5 + 0.53 = 5.53 (but this is to long just to make it clear)


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Step-by-step explanation:

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Answer:

<h2>See below</h2>

Step-by-step explanation:

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Graph photo shown in file called equation 1 graph

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Find the general indefinite integral. (use c for the constant of integration. )
Vlada [557]

The indefinite integral will be  \int (7x^2+8x-2)dx=\dfrac{7x^3}{3}+4x^2-2x+C)

<h3 /><h3>what is indefinite integral?</h3>

When we integrate any function without the limits then it will be an indefinite integral.

General Formulas and Concepts:

Integration Rule [Reverse Power Rule]:                                                              

\int x^ndx=\dfrac{x^{n+1}}{n+1}}+C

Integration Property [Multiplied Constant]:                                                        

\int cf(x)dx=c\int f(x)dx

Integration Property [Addition/Subtraction]:                                                      

\int [f(x)\pmg(x)]dx=\int f(x)dx\pm \intg(x)dx

[Integral] Rewrite [Integration Property - Addition/Subtraction]:

\int (7x^2+8x-2)dx=\int 7x^2dx+\int 8xdx    -\int 2dx          

[Integrals] Rewrite [Integration Property - Multiplied Constant]:  

\int (7x^2+8x-2)dx=7 \int x^2dx+ 8 \int xdx    -2\int dx            

[Integrals] Reverse Power Rule:    

\int (7x^2+8x-2)dx= 7(\dfrac{x^3}{3})+8(\dfrac{x^2}{2})-2x+C                                                            

Simplify:    

\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C                                                                                                      

So the indefinite integral will be \int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C                

To know more about indefinite integral follow

brainly.com/question/27419605

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