The answer is no. No matter how you do it two mixed numbers will never be a whole and even 2
Answer:
<em>Part A: 3,</em>
<em>Part B: - 4</em>
Step-by-step explanation:
<em>~ Part A ~ </em>
The problem would be in terms of such an expression: ( - 6 - ( - 3 )^2 )/ -5
Now knowing the expression, let us simplify in terms of basic algebra:
( -6 - 9 )/ -5 = ( - 15/ - 5 ) = <em>Answer; 3</em>
<em>~ Part B ~ </em>
We know the problem to be p^2/ r, but we must substitute the value of p being -10, and r ⇒ -25: ( - 10 )^2/ -25
Now let us simplify the expressions:
( - 10 )^2/ -25 = 100/ - 25 =<em> Answer; -4</em>
The entire line will go three to the left and one down.
Answer: 3x⁴ + x + 7
<u>Step-by-step explanation:</u>
(5x⁴ - 3x² + 7x - 10) - (2x⁴ - 3x³ + 6x - 17)
Distribute the negative to the second expression, which means "change all of the signs" and then add the two expressions.
( 5x⁴ - 3x² + 7x - 10)
+ <u>(-2x⁴ + 3x³ - 6x + 17)</u>
= 3x⁴ + 0x³ + 1x + 7
= 3x⁴ + x + 7
Note: If you need to show work for distributing the negative sign, multiply each term of the second expression by -1.
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Plan A = 10x + 144
Plan B = 48 + 22y
Equate them
10x + 144 = 22y + 48
22y - 10x = 144 - 48
22y - 10x = 96
divide by 2
11y - 5x = 48
What I did was just use trial and error at this point.
11(8) - 5(8) = 48
8 visits must a person make for plan A to plan B.
