So the perimeter(P) of a rectangle would be:
P= 2L+2W
L being the length and W being the width.
The problem says the length is 4cm more than the width, so L= 4+W.
So if we substitute L with 4+W, we get:
P= 2(4+W) + 2W
Use the Distributive Property
P= 8+2W+2W
Combine like terms
P=8+4W
Since we're given the perimeter, we could replace P with 52. So:
52=8+4W
Subtract 8 to both sides
44=4W
Divide 4 to both sides
11=W
Therefore, the width is 11cm
And since the length is 4cm more than the width, we could add 4cm to 11cm to find that the length is 15cm
Thus, the dimensions of the rectangle are 15cm by 11cm
Well that would be 8 apples in 4 bags so there’s 6
answer: 6
I believe C. Measuring the length from one end of the field tot he other would be the most reasonable answer, because Area = Length x Width
Answer:
Step-by-step explanation:
-This is an addition/subtraction problem.
#We subtract the sum of the first two expression from the third expression:
Hence, the expression must be added to the first two.
Formula for volume = length × width × height
21 * 7 = 147
9 1/3 = 28/3
147 * 28 /3 = 4116/3
Simplify :
4116/3 = 1372
Volume = 1372 cm³.
Hope this helped☺☺
