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Semmy [17]
3 years ago
11

h best describes the relationship between the successive terms in the sequence shown? 9, –1, –11, –21, … The common difference i

s –10. The common difference is 10. The common ratio is –9. The common ratio is 9.
Mathematics
1 answer:
My name is Ann [436]3 years ago
4 0
-1=9 + (-10)
-11=-1+ (-10)

⇒ the common ratio is    -10
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Complete the point-slope equation of the line through (-8,-1)(−8,−1)
ZanzabumX [31]

Answer:

The equation of the line is y = -1

Step-by-step explanation:

In order to find the equation,y = mx + c, you have to find the gradient first using the formula :

m =  \frac{y2 - y1}{x2 - x2}

Let (x1,y1) = (-8,-1) & (x2,y2) = (-8,-1),

m = (-1)-(-1)/-8-(-8)

= 0

Now, we have found the gradient, next using the formula, y = mx + c to find the equation :

y = mx + c

Let m=0,

At (-8,-1)

-1 = 0(-8) + c

c = -1

y = -1

6 0
3 years ago
Which best summarizes the purpose of a W-4 form?
Naya [18.7K]

Answer:

<u>A</u>.) It helps determine the amount of taxes withheld from an individual's paycheck.

Step-by-step explanation:

Got it correct on the quiz!

3 0
3 years ago
Read 2 more answers
The United States Bureau of Labor Statistics (BLS) conducts the Quarterly Census of Employment and Wages (QCEW) and reports a va
Lemur [1.5K]

Answer:

The mean total taxable earnings of all wage earners in a county is same as the population mean, $28.29.

The probability that the mean taxable wages in James' sample of 56 counties will be less than $33 million is 0.8508.

The probability that the mean taxable wages in James' sample of 56 counties will be greater than $30 million is 0.3520.

Step-by-step explanation:

Let <em>X</em> = total taxable earnings of workers.

The expected value of the random variable <em>X</em> is:

E (X) = <em>μ</em> = $28.29

The standard deviation of the random variable <em>X</em> is:

SD (X) = <em>σ</em> = $33.493.

The data was collected from 56 American counties.

The sample mean of a random variable is the an unbiased estimator of the population mean.

If repeated samples are collected from a population and the mean for each sample is computed then the expected value of the sample means is same as the population mean.

So the mean total taxable earnings of all wage earners in a county is same as the population mean, $28.29.

According to the Central limit theorem if we have a population with mean μ and standard deviation σ and take appropriately huge random-samples (n ≥ 30) from the population with replacement, then the distribution of the sample-means will be approximately normally distributed.

Then, the mean of the sample means is given by,  \mu_{\bar x}=\mu.

And the standard deviation of sample means is, \sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

Compute the value of P (\bar X < 33) as follows:

P(\bar X

Thus, the probability that the mean taxable wages in James' sample of 56 counties will be less than $33 million is 0.8508.

Compute the value of P (\bar X > 30) as follows:

P(\bar X>30)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{30-28.29}{33.943/\sqrt{56}})\\=P(Z>0.38)\\=1-P(Z

Thus, the probability that the mean taxable wages in James' sample of 56 counties will be greater than $30 million is 0.3520.

5 0
3 years ago
Factor out the common factor in -45 + 81n + 90n^2
IRISSAK [1]

A: I think it’s 9(−5+9n+10n2)

Step-by-step explanation:

6 0
3 years ago
A principal of $3900 is invested at 7.5% interest compounded annually how much will the investment be worth after 9 years
Paha777 [63]

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$3900\\ r=rate\to 7.5\%\to \frac{7.5}{100}\dotfill &0.075\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &9 \end{cases} \\\\\\ A=3900\left(1+\frac{0.075}{1}\right)^{1\cdot 9}\implies A=3900(1.075)^9\implies A\approx 7477.23

7 0
2 years ago
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