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2 years ago

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h best describes the relationship between the successive terms in the sequence shown? 9, –1, –11, –21, … The common difference i

s –10. The common difference is 10. The common ratio is –9. The common ratio is 9.

1 answer:

My name is Ann [436]2 years ago

4 0

-1=9 + (-10)
-11=-1+ (-10)

⇒ the common ratio is -10

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I can’t figure out how to use the zeros in the polynomial. Please explain

Temka [501]

Answer:

a) $P (x) = (x + 3) (x-1) (x-4)$

b) $P (x) = (2x + 5) (5x - 4) (x-6)$

c) $P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2$

Step-by-step explanation:

<u>For the question a *</u> you need to find a polynomial of degree 3 with zeros in -3, 1 and 4.

This means that the polynomial P(x) must be zero when x = -3, x = 1 and x = 4.

Then write the polynomial in factored form.

$P (x) = (x + 3) (x-1) (x-4)$

Note that this polynomial has degree 3 and is zero at x = -3, x = 1 and x = 4.

<u>For question b, do the same procedure</u>.

Degree: 3

Zeros: -5/2, 4/5, 6.

The factors are

$x = -\frac{5}{2}\\\\x +\frac{5}{2} = 0\\\\(2x +5) = 0$

---------------------------------------

$x =\frac{4}{5}\\\\x-\frac{4}{5} = 0\\\\(5x-4) = 0$

--------------------------------------

$x = 6\\\\(x-6) = 0$

--------------------------------------

$P (x) = (2x + 5) (5x - 4) (x-6)$

<u>Finally for the question c we have</u>

Degree: 5

Zeros: -3, 1, 4, -1

Multiplicity 2 in -1

$x = -3\\\\(x-3) = 0$

--------------------------------------

$x = 1\\\\(x-1) = 0$

--------------------------------------

$x = 4\\\\(x-4) = 0$

----------------------------------------

$x = -1\\\\(x + 1) = 0$

-----------------------------------------

$P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2$

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2 years ago

A circle has its center at (1, 4) and a radius of 2 units. What is the equation of the circle? (1 point) (x + 2)2 + (y + 4)2 = 2

yawa3891 [41]

Answer:

3rd one. The general form of a circle is set equal to the radius squared. So right side is 4 then plug in values until true.

5 0

3 years ago

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The standard form of the equation for a quadratic function is, with he vertex of the graph of the function at the point (p,q). t

ludmilkaskok [199]

Answer:

p = ½ (x₁ + x₂)

q = a (x₁x₂ − ¼ (x₁ + x₂)²)

Step-by-step explanation:

y = a (x − x₁) (x − x₂)

Expand:

y = a (x² − x₁x − x₂x + x₁x₂)

y = a (x² − (x₁ + x₂)x + x₁x₂)

Distribute a to the first two terms:

y = a (x² − (x₁ + x₂)x) + ax₁x₂

Complete the square:

y = a (x² − (x₁ + x₂)x + ¼(x₁ + x₂)²) + ax₁x₂ − ¼ a(x₁ + x₂)²

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Therefore:

p = ½ (x₁ + x₂)

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Answer:

2

Step-by-step explanation:

if you multiply 2 by 3=6

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Answer:

I think right answer is integers

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