The instantaneous rate of change of the function f(x) = −4x² − 3x + 1 at the point x = -3 is 21.
<h3>What is the instantaneous rate of change of the function at the given point?</h3>
The instantaneous rate of change is simply the change in the derivative value at a specific point.
Given the data in the question;
- f(x) = −4x² − 3x + 1
- Point x = -3
To determine the instantaneous rate of change of the function, first find the derivative of the function.
f(x) = −4x² − 3x + 1
Applying sum rule, with respect to x
d/dx[ -4x² ] + d/dx[ -3x ] + d/dx[ 1 ]
[ 2 × -4x¹ ] + [ 1 × -3x⁰ ] + d/dx[ 1 ]
[ -8x ] + [ -3 ] + d/dx[ 1 ]
-8x - 3 + d/dx[ 1 ]
Differentiate using constant rule
-8x - 3 + [ 0 ]
-8x - 3
f'(x) = -8x - 3
Next, plug x = -3 into the derivative and simplify.
f'(x) = -8x - 3
f'(-3) = -8(-3) - 3
f'(-3) = 24 - 3
f'(-3) = 21
Therefore, the instantaneous rate of change of the function f(x) = −4x² − 3x + 1 at the point x = -3 is 21.
Learn more about instantaneous rate of change here: brainly.com/question/28122560
#SPJ1
Answer:
201.6 = 11.2f
Step-by-step explanation:
The yearly salary after paying for taxes, insurances and other expenses is r808.42.
<h3>What is the yearly salary?</h3>
The first step is to determine the total fraction used to pay for taxes, insurances and other expenses:
1/2 + 1/16 + 5/6
(48 + 6 + 80) / 96 = 134 / 96= 1 19/48
Now subtract 1 19/48 from 1
1 19/48 - 1 = 19/48
Finally, divide 19/48 by 320
320 x 48/19 = r808.42
To learn more about the division of fractions, please check: brainly.com/question/25779356
The Pythagorean Theorem states that a^2+b^2=c^2
We already have:
A^2+6^2=117
All we need to do is find the missing A by subtract b from c.
117-36=81
Now the square root of 81, 9.
So, x is 9 cm.
Answer:
an open circle on -1.3 on the line and draw a line to the right with an arrow.
Step-by-step explanation:
On your number line, draw an open circle on -1.3 and then draw a line on the number line going to the right and ending with an arrow at the end. The open circle means that it is that starting point, but is not equal to it.