I believe the max would be 195ml. Hope this helps :)
Answer:
y=2x-8 x=12 y=16
Step-by-step explanation:
the function is y=2x-8
if x=12
y= 2 (12)-8=16
Answer:
The area which the cow can graze is 2199.115 m²
Step-by-step explanation:
Here we have;
Size of barn = 20 m by 35 m
Length of the cow's rope = 30 m
The cow, can graze an area given by a circle of radius equal to the length of the cows rope less the segment where the barn is located hence, we have;
The length of the barn > The length of the cow's rope
The width of the barn < The width of the cow's rope, therefore, the cow can graze approximately 3/4 of the circle of radius 30 m which is 3/4×π×30² = 2120.575 m²
The cow can also graze on the adjacent side of the barn after crossing the width of the barn in an area of 1/4×π×(30 - 20)² = 78.54 m²
Hence the total area the cow can graze while the cow is tethered to the external corner of the rectangular barn = 2120.575 m² + 78.54 m² = 2199.115 m².
Answer:
SB or ? = 9
Step-by-step explanation:
Since the two triangles are similar.
((18 + 6) / 6) = 24 / 6 = <u>4</u>
[Scale factor between ∆BCU and ∆SUT]
SB or ? = 12 – 12/<u>4</u> = 12 – 3 = 9
Answer:
2 and -9
Step-by-step explanation:
2 times -9 is -18
2 plus -9 is -7
Hope this helped!
