Answer:
0.026
Step-by-step explanation:
Given the result of 10 coin flips :
T,T,H,T,H,T,T,T,H,T
Number of Heads, H = 3
Number of tails, T = 7
Let :
B = biased coin
B' = non-biased coin
E = event
Probability that it is the biased coin:
P(E Given biased coin) / P(E Given biased coin) * P(E Given non-biased coin) * P(non-biased coin)
P(E|B)P(B) / (P(E|B)*P(B) + P(E|B')P(B')
([(0.75^3) * (0.25^7)] * 0.5) /([(0.75^3) * (0.25^7)] * 0.5) + (0.5^10) * 0.5
0.0000128746 / 0.00050115585
= 0.0263671875
9514 1404 393
Answer:
10 1/16 cm
Step-by-step explanation:
The Pythagorean theorem can be used.
(8 +x)² = x² +15²
64 +16x +x² = x² +225
16x = 161
x = 161/16 = 10 1/16 = 10.0625 . . . cm
Answer:
Step-by-step explanation:
This is simply a units conversion problem. It gives us for the number of passengers, the number of seats per carriage and the number of carriages per train. To change the units from passengers to trains without changing the value, we use the multiplicative identity (that is, 1).
350000 passengers
(350000 passengers) * 1
(350000 passengers) * ((1 carriage)/(32 passengers)) * ((1 train)/(15 carriages)
[note: passengers and carriages cancel. Leaving only trains]
(350000)*(1/32)*(1/15) trains [note: I write this way to paste into MS Excel]
729.1667 trains [oh, but don’t just round this number either up or down]
729 full trains can carry 729*32*15 = 349920 passengers
730 full trains can carry 730*32*15 = 350400 passengers
Now, we can say that 730 trains are adequate to carry 350000 passengers.
Answer:
12x-21
Step-by-step explanation:
Take the point (10,5)
5 = constant / 10
constant = 5*10 = 50
also for the point (4 , 12.5) constant = 4*12.5 = 50
Answer is 50
