Question

PLEASE ANSWER THIS MATH QUESTION FOR THOSE MATH LOVERS :)

Answer 1

Remark

The general formula for these types of questions is

(x1 + k(x2 - x1) ) , (y1 + k(y2 - y1))

Problem 1 -- Point G

Givens

(x1,y1) is the starting point which in this case is (-3, -3)

(x2,y2) is the ending point which in this case is (6 , -3)

k = 1/4

Sub and solve

(-3 + 1/4(6 - - 3), - 3+ 1/4(- 3 - - 3)

(-3 + 1/4(9) , - 3 + 1/4 (-3 + 3)

(-3 + 9/4, -3 + 1/4(0) )

(-12/4 + 9/4 , -3)

(-3/4 , - 3) Answer

Problem 2 Point F Much harder

Givens

(x1,y1) = (-3 , -1)

(x2,y2) = (6, - 3)

k = 3/4

Sub and solve

(-3 + 3/4(6 - - 3) , -1 + 3/4(-3 - - 1) )

(-3 + 3/4(9) , - 1 + 3/4(-2) )

(-3 + 27/4 , -1 - 6/4 )

(-12/4 + 27/4, -4/4 - 6/4)

( 15/4 , - 10/4) <<<<<< Answer Part B

Answer 2

There are 4 equal divisions between Q and B and x coordinates are -3 to 6 - that's 9 units so x coordinate of G are (-3+ 9/4 , -3)

= ( -3/4 , -3) Answer

Point F:-

This is (-3 + 3(9/4) , -5/2)

= (15/4, -5/2) answer